{ "data": { "question": { "questionId": "3383", "questionFrontendId": "3147", "categoryTitle": "Algorithms", "boundTopicId": 2773142, "title": "Taking Maximum Energy From the Mystic Dungeon", "titleSlug": "taking-maximum-energy-from-the-mystic-dungeon", "content": "
In a mystic dungeon, n magicians are standing in a line. Each magician has an attribute that gives you energy. Some magicians can give you negative energy, which means taking energy from you.
You have been cursed in such a way that after absorbing energy from magician i, you will be instantly transported to magician (i + k). This process will be repeated until you reach the magician where (i + k) does not exist.
In other words, you will choose a starting point and then teleport with k jumps until you reach the end of the magicians' sequence, absorbing all the energy during the journey.
You are given an array energy and an integer k. Return the maximum possible energy you can gain.
Note that when you are reach a magician, you must take energy from them, whether it is negative or positive energy.
\n\n\n
Example 1:
\n\nInput: energy = [5,2,-10,-5,1], k = 3
\n\nOutput: 3
\n\nExplanation: We can gain a total energy of 3 by starting from magician 1 absorbing 2 + 1 = 3.
\nExample 2:
\n\nInput: energy = [-2,-3,-1], k = 2
\n\nOutput: -1
\n\nExplanation: We can gain a total energy of -1 by starting from magician 2.
\n\n
Constraints:
\n\n1 <= energy.length <= 105-1000 <= energy[i] <= 10001 <= k <= energy.length - 1\n", "translatedTitle": "从魔法师身上吸取的最大能量", "translatedContent": "
在神秘的地牢中,n 个魔法师站成一排。每个魔法师都拥有一个属性,这个属性可以给你提供能量。有些魔法师可能会给你负能量,即从你身上吸取能量。
你被施加了一种诅咒,当你从魔法师 i 处吸收能量后,你将被立即传送到魔法师 (i + k) 处。这一过程将重复进行,直到你到达一个不存在 (i + k) 的魔法师为止。
换句话说,你将选择一个起点,然后以 k 为间隔跳跃,直到到达魔法师序列的末端,在过程中吸收所有的能量。
给定一个数组 energy 和一个整数k,返回你能获得的 最大 能量。
\n\n
示例 1:
\n\n输入: energy = [5,2,-10,-5,1], k = 3
\n\n输出: 3
\n\n解释:可以从魔法师 1 开始,吸收能量 2 + 1 = 3。
\n示例 2:
\n\n输入: energy = [-2,-3,-1], k = 2
\n\n输出: -1
\n\n解释:可以从魔法师 2 开始,吸收能量 -1。
\n\n\n
提示:
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dp[i] denote the energy we gain starting from index i.",
"We can notice, that dp[i] = dp[i + k] + energy[i]."
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