{ "data": { "question": { "questionId": "2887", "questionFrontendId": "2785", "categoryTitle": "Algorithms", "boundTopicId": 2352508, "title": "Sort Vowels in a String", "titleSlug": "sort-vowels-in-a-string", "content": "
Given a 0-indexed string s, permute s to get a new string t such that:
i with 0 <= i < s.length such that s[i] is a consonant, then t[i] = s[i].i, j with 0 <= i < j < s.length such that s[i] and s[j] are vowels, then t[i] must not have a higher ASCII value than t[j].Return the resulting string.
\n\nThe vowels are 'a', 'e', 'i', 'o', and 'u', and they can appear in lowercase or uppercase. Consonants comprise all letters that are not vowels.
\n
Example 1:
\n\n\nInput: s = "lEetcOde"\nOutput: "lEOtcede"\nExplanation: 'E', 'O', and 'e' are the vowels in s; 'l', 't', 'c', and 'd' are all consonants. The vowels are sorted according to their ASCII values, and the consonants remain in the same places.\n\n\n
Example 2:
\n\n\nInput: s = "lYmpH"\nOutput: "lYmpH"\nExplanation: There are no vowels in s (all characters in s are consonants), so we return "lYmpH".\n\n\n
\n
Constraints:
\n\n1 <= s.length <= 105s consists only of letters of the English alphabet in uppercase and lowercase.给你一个下标从 0 开始的字符串 s ,将 s 中的元素重新 排列 得到新的字符串 t ,它满足:
0 <= i < s.length 的下标 i 处的 s[i] 是个辅音字母,那么 t[i] = s[i] 。0 <= i < j < s.length 的下标 i 和 j ,如果 s[i] 和 s[j] 都是元音字母,那么 t[i] 的 ASCII 值不能大于 t[j] 的 ASCII 值。请你返回结果字母串。
\n\n元音字母为 'a' ,'e' ,'i' ,'o' 和 'u' ,它们可能是小写字母也可能是大写字母,辅音字母是除了这 5 个字母以外的所有字母。
\n\n
示例 1:
\n\n\n输入:s = \"lEetcOde\"\n输出:\"lEOtcede\"\n解释:'E' ,'O' 和 'e' 是 s 中的元音字母,'l' ,'t' ,'c' 和 'd' 是所有的辅音。将元音字母按照 ASCII 值排序,辅音字母留在原地。\n\n\n
示例 2:
\n\n\n输入:s = \"lYmpH\"\n输出:\"lYmpH\"\n解释:s 中没有元音字母(s 中都为辅音字母),所以我们返回 \"lYmpH\" 。\n\n\n
\n\n
提示:
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