![\"\"](\"https://assets.leetcode.com/uploads/2023/03/06/screenshot-2023-03-06-at-45648-pm.png\")
You are given a 0-indexed two-dimensional integer array nums.
Return the largest prime number that lies on at least one of the diagonals of nums. In case, no prime is present on any of the diagonals, return 0.
Note that:
\n\n1 and has no positive integer divisors other than 1 and itself.val is on one of the diagonals of nums if there exists an integer i for which nums[i][i] = val or an i for which nums[i][nums.length - i - 1] = val.
In the above diagram, one diagonal is [1,5,9] and another diagonal is [3,5,7].
\n\n\n
Example 1:
\n\n\nInput: nums = [[1,2,3],[5,6,7],[9,10,11]]\nOutput: 11\nExplanation: The numbers 1, 3, 6, 9, and 11 are the only numbers present on at least one of the diagonals. Since 11 is the largest prime, we return 11.\n\n\n
Example 2:
\n\n\nInput: nums = [[1,2,3],[5,17,7],[9,11,10]]\nOutput: 17\nExplanation: The numbers 1, 3, 9, 10, and 17 are all present on at least one of the diagonals. 17 is the largest prime, so we return 17.\n\n\n
\n
Constraints:
\n\n1 <= nums.length <= 300nums.length == numsi.length1 <= nums[i][j] <= 4*106给你一个下标从 0 开始的二维整数数组 nums 。
返回位于 nums 至少一条 对角线 上的最大 质数 。如果任一对角线上均不存在质数，返回 0 。
注意：
\n\n1 ，且不存在除 1 和自身之外的正整数因子，则认为该整数是一个质数。i ，使得 nums[i][i] = val 或者 nums[i][nums.length - i - 1]= val ，则认为整数 val 位于 nums 的一条对角线上。
在上图中，一条对角线是 [1,5,9] ，而另一条对角线是 [3,5,7] 。
\n\n\n\n
示例 1：
\n\n\n输入：nums = [[1,2,3],[5,6,7],[9,10,11]]\n输出：11\n解释：数字 1、3、6、9 和 11 是所有 \"位于至少一条对角线上\" 的数字。由于 11 是最大的质数，故返回 11 。\n\n\n
示例 2：
\n\n\n输入：nums = [[1,2,3],[5,17,7],[9,11,10]]\n输出：17\n解释：数字 1、3、9、10 和 17 是所有满足\"位于至少一条对角线上\"的数字。由于 17 是最大的质数，故返回 17 。\n\n\n
\n\n
提示：
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"exampleTestcases": "[[1,2,3],[5,6,7],[9,10,11]]\n[[1,2,3],[5,17,7],[9,11,10]]",
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