You are given an array time where time[i] denotes the time taken by the ith bus to complete one trip.
Each bus can make multiple trips successively; that is, the next trip can start immediately after completing the current trip. Also, each bus operates independently; that is, the trips of one bus do not influence the trips of any other bus.
\n\nYou are also given an integer totalTrips, which denotes the number of trips all buses should make in total. Return the minimum time required for all buses to complete at least totalTrips trips.
\n
Example 1:
\n\n\nInput: time = [1,2,3], totalTrips = 5\nOutput: 3\nExplanation:\n- At time t = 1, the number of trips completed by each bus are [1,0,0]. \n The total number of trips completed is 1 + 0 + 0 = 1.\n- At time t = 2, the number of trips completed by each bus are [2,1,0]. \n The total number of trips completed is 2 + 1 + 0 = 3.\n- At time t = 3, the number of trips completed by each bus are [3,1,1]. \n The total number of trips completed is 3 + 1 + 1 = 5.\nSo the minimum time needed for all buses to complete at least 5 trips is 3.\n\n\n
Example 2:
\n\n\nInput: time = [2], totalTrips = 1\nOutput: 2\nExplanation:\nThere is only one bus, and it will complete its first trip at t = 2.\nSo the minimum time needed to complete 1 trip is 2.\n\n\n
\n
Constraints:
\n\n1 <= time.length <= 1051 <= time[i], totalTrips <= 107给你一个数组 time ，其中 time[i] 表示第 i 辆公交车完成 一趟旅途 所需要花费的时间。
每辆公交车可以 连续 完成多趟旅途，也就是说，一辆公交车当前旅途完成后，可以 立马开始 下一趟旅途。每辆公交车 独立 运行，也就是说可以同时有多辆公交车在运行且互不影响。
\n\n给你一个整数 totalTrips ，表示所有公交车 总共 需要完成的旅途数目。请你返回完成 至少 totalTrips 趟旅途需要花费的 最少 时间。
\n\n
示例 1：
\n\n输入：time = [1,2,3], totalTrips = 5\n输出：3\n解释：\n- 时刻 t = 1 ，每辆公交车完成的旅途数分别为 [1,0,0] 。\n 已完成的总旅途数为 1 + 0 + 0 = 1 。\n- 时刻 t = 2 ，每辆公交车完成的旅途数分别为 [2,1,0] 。\n 已完成的总旅途数为 2 + 1 + 0 = 3 。\n- 时刻 t = 3 ，每辆公交车完成的旅途数分别为 [3,1,1] 。\n 已完成的总旅途数为 3 + 1 + 1 = 5 。\n所以总共完成至少 5 趟旅途的最少时间为 3 。\n\n\n
示例 2：
\n\n输入：time = [2], totalTrips = 1\n输出：2\n解释：\n只有一辆公交车，它将在时刻 t = 2 完成第一趟旅途。\n所以完成 1 趟旅途的最少时间为 2 。\n\n\n
\n\n
提示：
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