You are given an array nums consisting of positive integers.
You are also given an integer array queries of size m. For the ith query, you want to make all of the elements of nums equal to queries[i]. You can perform the following operation on the array any number of times:
1.Return an array answer of size m where answer[i] is the minimum number of operations to make all elements of nums equal to queries[i].
Note that after each query the array is reset to its original state.
\n\n\n
Example 1:
\n\n\nInput: nums = [3,1,6,8], queries = [1,5]\nOutput: [14,10]\nExplanation: For the first query we can do the following operations:\n- Decrease nums[0] 2 times, so that nums = [1,1,6,8].\n- Decrease nums[2] 5 times, so that nums = [1,1,1,8].\n- Decrease nums[3] 7 times, so that nums = [1,1,1,1].\nSo the total number of operations for the first query is 2 + 5 + 7 = 14.\nFor the second query we can do the following operations:\n- Increase nums[0] 2 times, so that nums = [5,1,6,8].\n- Increase nums[1] 4 times, so that nums = [5,5,6,8].\n- Decrease nums[2] 1 time, so that nums = [5,5,5,8].\n- Decrease nums[3] 3 times, so that nums = [5,5,5,5].\nSo the total number of operations for the second query is 2 + 4 + 1 + 3 = 10.\n\n\n
Example 2:
\n\n\nInput: nums = [2,9,6,3], queries = [10]\nOutput: [20]\nExplanation: We can increase each value in the array to 10. The total number of operations will be 8 + 1 + 4 + 7 = 20.\n\n\n
\n
Constraints:
\n\nn == nums.lengthm == queries.length1 <= n, m <= 1051 <= nums[i], queries[i] <= 109给你一个正整数数组 nums 。
同时给你一个长度为 m 的整数数组 queries 。第 i 个查询中，你需要将 nums 中所有元素变成 queries[i] 。你可以执行以下操作 任意 次：
1 。请你返回一个长度为 m 的数组 answer ，其中 answer[i]是将 nums 中所有元素变成 queries[i] 的 最少 操作次数。
注意，每次查询后，数组变回最开始的值。
\n\n\n\n
示例 1：
\n\n输入：nums = [3,1,6,8], queries = [1,5]\n输出：[14,10]\n解释：第一个查询，我们可以执行以下操作：\n- 将 nums[0] 减小 2 次，nums = [1,1,6,8] 。\n- 将 nums[2] 减小 5 次，nums = [1,1,1,8] 。\n- 将 nums[3] 减小 7 次，nums = [1,1,1,1] 。\n第一个查询的总操作次数为 2 + 5 + 7 = 14 。\n第二个查询，我们可以执行以下操作：\n- 将 nums[0] 增大 2 次，nums = [5,1,6,8] 。\n- 将 nums[1] 增大 4 次，nums = [5,5,6,8] 。\n- 将 nums[2] 减小 1 次，nums = [5,5,5,8] 。\n- 将 nums[3] 减小 3 次，nums = [5,5,5,5] 。\n第二个查询的总操作次数为 2 + 4 + 1 + 3 = 10 。\n\n\n
示例 2：
\n\n输入：nums = [2,9,6,3], queries = [10]\n输出：[20]\n解释：我们可以将数组中所有元素都增大到 10 ，总操作次数为 8 + 1 + 4 + 7 = 20 。\n\n\n
\n\n
提示：
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