You are given a 0-indexed integer array nums, and an integer k.
In one operation, you can remove one occurrence of the smallest element of nums.
Return the minimum number of operations needed so that all elements of the array are greater than or equal to k.
\n
Example 1:
\n\n\nInput: nums = [2,11,10,1,3], k = 10\nOutput: 3\nExplanation: After one operation, nums becomes equal to [2, 11, 10, 3].\nAfter two operations, nums becomes equal to [11, 10, 3].\nAfter three operations, nums becomes equal to [11, 10].\nAt this stage, all the elements of nums are greater than or equal to 10 so we can stop.\nIt can be shown that 3 is the minimum number of operations needed so that all elements of the array are greater than or equal to 10.\n\n\n
Example 2:
\n\n\nInput: nums = [1,1,2,4,9], k = 1\nOutput: 0\nExplanation: All elements of the array are greater than or equal to 1 so we do not need to apply any operations on nums.\n\n
Example 3:
\n\n\nInput: nums = [1,1,2,4,9], k = 9\nOutput: 4\nExplanation: only a single element of nums is greater than or equal to 9 so we need to apply the operations 4 times on nums.\n\n\n
\n
Constraints:
\n\n1 <= nums.length <= 501 <= nums[i] <= 1091 <= k <= 109i such that nums[i] >= k.给你一个下标从 0 开始的整数数组 nums 和一个整数 k 。
一次操作中，你可以删除 nums 中的最小元素。
你需要使数组中的所有元素都大于或等于 k ，请你返回需要的 最少 操作次数。
\n\n
示例 1：
\n\n\n输入：nums = [2,11,10,1,3], k = 10\n输出：3\n解释：第一次操作后，nums 变为 [2, 11, 10, 3] 。\n第二次操作后，nums 变为 [11, 10, 3] 。\n第三次操作后，nums 变为 [11, 10] 。\n此时，数组中的所有元素都大于等于 10 ，所以我们停止操作。\n使数组中所有元素都大于等于 10 需要的最少操作次数为 3 。\n\n\n
示例 2：
\n\n\n输入：nums = [1,1,2,4,9], k = 1\n输出：0\n解释：数组中的所有元素都大于等于 1 ，所以不需要对 nums 做任何操作。\n\n
示例 3：
\n\n\n输入：nums = [1,1,2,4,9], k = 9\n输出：4\n解释：nums 中只有一个元素大于等于 9 ，所以需要执行 4 次操作。\n\n\n
\n\n
提示：
\n\n1 <= nums.length <= 501 <= nums[i] <= 1091 <= k <= 109nums[i] >= k 的下标 i 存在。nums and count the number of elements less than k."
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