You are given two strings current and correct representing two 24-hour times.
24-hour times are formatted as "HH:MM", where HH is between 00 and 23, and MM is between 00 and 59. The earliest 24-hour time is 00:00, and the latest is 23:59.
In one operation you can increase the time current by 1, 5, 15, or 60 minutes. You can perform this operation any number of times.
Return the minimum number of operations needed to convert current to correct.
\n
Example 1:
\n\n\nInput: current = "02:30", correct = "04:35"\nOutput: 3\nExplanation:\nWe can convert current to correct in 3 operations as follows:\n- Add 60 minutes to current. current becomes "03:30".\n- Add 60 minutes to current. current becomes "04:30".\n- Add 5 minutes to current. current becomes "04:35".\nIt can be proven that it is not possible to convert current to correct in fewer than 3 operations.\n\n
Example 2:
\n\n\nInput: current = "11:00", correct = "11:01"\nOutput: 1\nExplanation: We only have to add one minute to current, so the minimum number of operations needed is 1.\n\n\n
\n
Constraints:
\n\ncurrent and correct are in the format "HH:MM"current <= correct给你两个字符串 current 和 correct ，表示两个 24 小时制时间 。
24 小时制时间 按 \"HH:MM\" 进行格式化，其中 HH 在 00 和 23 之间，而 MM 在 00 和 59 之间。最早的 24 小时制时间为 00:00 ，最晚的是 23:59 。
在一步操作中，你可以将 current 这个时间增加 1、5、15 或 60 分钟。你可以执行这一操作 任意 次数。
返回将 current 转化为 correct 需要的 最少操作数 。
\n\n
示例 1：
\n\n输入：current = \"02:30\", correct = \"04:35\"\n输出：3\n解释：\n可以按下述 3 步操作将 current 转换为 correct ：\n- 为 current 加 60 分钟，current 变为 \"03:30\" 。\n- 为 current 加 60 分钟，current 变为 \"04:30\" 。 \n- 为 current 加 5 分钟，current 变为 \"04:35\" 。\n可以证明，无法用少于 3 步操作将 current 转化为 correct 。\n\n
示例 2：
\n\n输入：current = \"11:00\", correct = \"11:01\"\n输出：1\n解释：只需要为 current 加一分钟，所以最小操作数是 1 。\n\n\n
\n\n
提示：
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"book": null,
"isSubscribed": false,
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"editorType": "CKEDITOR",
"ugcQuestionId": null,
"style": "LEETCODE",
"exampleTestcases": "\"02:30\"\n\"04:35\"\n\"11:00\"\n\"11:01\"",
"__typename": "QuestionNode"
}
}
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