You are given two positive integer arrays nums and numsDivide. You can delete any number of elements from nums.
Return the minimum number of deletions such that the smallest element in nums divides all the elements of numsDivide. If this is not possible, return -1.
Note that an integer x divides y if y % x == 0.
\n
Example 1:
\n\n\nInput: nums = [2,3,2,4,3], numsDivide = [9,6,9,3,15]\nOutput: 2\nExplanation: \nThe smallest element in [2,3,2,4,3] is 2, which does not divide all the elements of numsDivide.\nWe use 2 deletions to delete the elements in nums that are equal to 2 which makes nums = [3,4,3].\nThe smallest element in [3,4,3] is 3, which divides all the elements of numsDivide.\nIt can be shown that 2 is the minimum number of deletions needed.\n\n\n
Example 2:
\n\n\nInput: nums = [4,3,6], numsDivide = [8,2,6,10]\nOutput: -1\nExplanation: \nWe want the smallest element in nums to divide all the elements of numsDivide.\nThere is no way to delete elements from nums to allow this.\n\n
\n
Constraints:
\n\n1 <= nums.length, numsDivide.length <= 1051 <= nums[i], numsDivide[i] <= 109给你两个正整数数组 nums 和 numsDivide 。你可以从 nums 中删除任意数目的元素。
请你返回使 nums 中 最小 元素可以整除 numsDivide 中所有元素的 最少 删除次数。如果无法得到这样的元素，返回 -1 。
如果 y % x == 0 ，那么我们说整数 x 整除 y 。
\n\n
示例 1：
\n\n输入：nums = [2,3,2,4,3], numsDivide = [9,6,9,3,15]\n输出：2\n解释：\n[2,3,2,4,3] 中最小元素是 2 ，它无法整除 numsDivide 中所有元素。\n我们从 nums 中删除 2 个大小为 2 的元素，得到 nums = [3,4,3] 。\n[3,4,3] 中最小元素为 3 ，它可以整除 numsDivide 中所有元素。\n可以证明 2 是最少删除次数。\n\n\n
示例 2：
\n\n输入：nums = [4,3,6], numsDivide = [8,2,6,10]\n输出：-1\n解释：\n我们想 nums 中的最小元素可以整除 numsDivide 中的所有元素。\n没有任何办法可以达到这一目的。\n\n
\n\n
提示：
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