{ "data": { "question": { "questionId": "2008", "questionFrontendId": "1896", "categoryTitle": "Algorithms", "boundTopicId": 820494, "title": "Minimum Cost to Change the Final Value of Expression", "titleSlug": "minimum-cost-to-change-the-final-value-of-expression", "content": "
You are given a valid boolean expression as a string expression consisting of the characters '1','0','&' (bitwise AND operator),'|' (bitwise OR operator),'(', and ')'.
"()1|1" and "(1)&()" are not valid while "1", "(((1))|(0))", and "1|(0&(1))" are valid expressions.Return the minimum cost to change the final value of the expression.
\n\nexpression = "1|1|(0&0)&1", its value is 1|1|(0&0)&1 = 1|1|0&1 = 1|0&1 = 1&1 = 1. We want to apply operations so that the new expression evaluates to 0.The cost of changing the final value of an expression is the number of operations performed on the expression. The types of operations are described as follows:
\n\n'1' into a '0'.'0' into a '1'.'&' into a '|'.'|' into a '&'.Note: '&' does not take precedence over '|' in the order of calculation. Evaluate parentheses first, then in left-to-right order.
\n
Example 1:
\n\n\nInput: expression = "1&(0|1)"\nOutput: 1\nExplanation: We can turn "1&(0|1)" into "1&(0&1)" by changing the '|' to a '&' using 1 operation.\nThe new expression evaluates to 0. \n\n\n
Example 2:
\n\n\nInput: expression = "(0&0)&(0&0&0)"\nOutput: 3\nExplanation: We can turn "(0&0)&(0&0&0)" into "(0|1)|(0&0&0)" using 3 operations.\nThe new expression evaluates to 1.\n\n\n
Example 3:
\n\n\nInput: expression = "(0|(1|0&1))"\nOutput: 1\nExplanation: We can turn "(0|(1|0&1))" into "(0|(0|0&1))" using 1 operation.\nThe new expression evaluates to 0.\n\n
\n
Constraints:
\n\n1 <= expression.length <= 105expression only contains '1','0','&','|','(', and ')'"()" is not a substring of expression).给你一个 有效的 布尔表达式,用字符串 expression 表示。这个字符串包含字符 '1','0','&'(按位 与 运算),'|'(按位 或 运算),'(' 和 ')' 。
\"()1|1\" 和 \"(1)&()\" 不是有效 布尔表达式。而 \"1\", \"(((1))|(0))\" 和 \"1|(0&(1))\" 是 有效 布尔表达式。你的目标是将布尔表达式的 值 反转 (也就是将 0 变为 1 ,或者将 1 变为 0),请你返回达成目标需要的 最少操作 次数。
expression = \"1|1|(0&0)&1\" ,它的 值 为 1|1|(0&0)&1 = 1|1|0&1 = 1|0&1 = 1&1 = 1 。我们想要执行操作将 新的 表达式的值变成 0 。可执行的 操作 如下:
\n\n'1' 变成一个 '0' 。'0' 变成一个 '1' 。'&' 变成一个 '|' 。'|' 变成一个 '&' 。注意:'&' 的 运算优先级 与 '|' 相同 。计算表达式时,括号优先级 最高 ,然后按照 从左到右 的顺序运算。
\n\n
示例 1:
\n\n输入:expression = \"1&(0|1)\"\n输出:1\n解释:我们可以将 \"1&(0|1)\" 变成 \"1&(0&1)\" ,执行的操作为将一个 '|' 变成一个 '&' ,执行了 1 次操作。\n新表达式的值为 0 。\n\n\n
示例 2:
\n\n输入:expression = \"(0&0)&(0&0&0)\"\n输出:3\n解释:我们可以将 \"(0&0)&(0&0&0)\" 变成 \"(0|1)|(0&0&0)\" ,执行了 3 次操作。\n新表达式的值为 1 。\n\n\n
示例 3:
\n\n输入:expression = \"(0|(1|0&1))\"\n输出:1\n解释:我们可以将 \"(0|(1|0&1))\" 变成 \"(0|(0|0&1))\" ,执行了 1 次操作。\n新表达式的值为 0 。\n\n
\n\n
提示:
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"exampleTestcases": "\"1&(0|1)\"\n\"(0&0)&(0&0&0)\"\n\"(0|(1|0&1))\"",
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