{ "data": { "question": { "questionId": "2135", "questionFrontendId": "2025", "categoryTitle": "Algorithms", "boundTopicId": 1026108, "title": "Maximum Number of Ways to Partition an Array", "titleSlug": "maximum-number-of-ways-to-partition-an-array", "content": "
You are given a 0-indexed integer array nums of length n. The number of ways to partition nums is the number of pivot indices that satisfy both conditions:
1 <= pivot < nnums[0] + nums[1] + ... + nums[pivot - 1] == nums[pivot] + nums[pivot + 1] + ... + nums[n - 1]You are also given an integer k. You can choose to change the value of one element of nums to k, or to leave the array unchanged.
Return the maximum possible number of ways to partition nums to satisfy both conditions after changing at most one element.
\n
Example 1:
\n\n\nInput: nums = [2,-1,2], k = 3\nOutput: 1\nExplanation: One optimal approach is to change nums[0] to k. The array becomes [3,-1,2].\nThere is one way to partition the array:\n- For pivot = 2, we have the partition [3,-1 | 2]: 3 + -1 == 2.\n\n\n
Example 2:
\n\n\nInput: nums = [0,0,0], k = 1\nOutput: 2\nExplanation: The optimal approach is to leave the array unchanged.\nThere are two ways to partition the array:\n- For pivot = 1, we have the partition [0 | 0,0]: 0 == 0 + 0.\n- For pivot = 2, we have the partition [0,0 | 0]: 0 + 0 == 0.\n\n\n
Example 3:
\n\n\nInput: nums = [22,4,-25,-20,-15,15,-16,7,19,-10,0,-13,-14], k = -33\nOutput: 4\nExplanation: One optimal approach is to change nums[2] to k. The array becomes [22,4,-33,-20,-15,15,-16,7,19,-10,0,-13,-14].\nThere are four ways to partition the array.\n\n\n
\n
Constraints:
\n\nn == nums.length2 <= n <= 105-105 <= k, nums[i] <= 105给你一个下标从 0 开始且长度为 n 的整数数组 nums 。分割 数组 nums 的方案数定义为符合以下两个条件的 pivot 数目:
1 <= pivot < nnums[0] + nums[1] + ... + nums[pivot - 1] == nums[pivot] + nums[pivot + 1] + ... + nums[n - 1]同时给你一个整数 k 。你可以将 nums 中 一个 元素变为 k 或 不改变 数组。
请你返回在 至多 改变一个元素的前提下,最多 有多少种方法 分割 nums 使得上述两个条件都满足。
\n\n
示例 1:
\n\n输入:nums = [2,-1,2], k = 3\n输出:1\n解释:一个最优的方案是将 nums[0] 改为 k 。数组变为 [3,-1,2] 。\n有一种方法分割数组:\n- pivot = 2 ,我们有分割 [3,-1 | 2]:3 + -1 == 2 。\n\n\n
示例 2:
\n\n输入:nums = [0,0,0], k = 1\n输出:2\n解释:一个最优的方案是不改动数组。\n有两种方法分割数组:\n- pivot = 1 ,我们有分割 [0 | 0,0]:0 == 0 + 0 。\n- pivot = 2 ,我们有分割 [0,0 | 0]: 0 + 0 == 0 。\n\n\n
示例 3:
\n\n输入:nums = [22,4,-25,-20,-15,15,-16,7,19,-10,0,-13,-14], k = -33\n输出:4\n解释:一个最优的方案是将 nums[2] 改为 k 。数组变为 [22,4,-33,-20,-15,15,-16,7,19,-10,0,-13,-14] 。\n有四种方法分割数组。\n\n\n
\n\n
提示:
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