{ "data": { "question": { "questionId": "2614", "questionFrontendId": "2529", "categoryTitle": "Algorithms", "boundTopicId": 2047515, "title": "Maximum Count of Positive Integer and Negative Integer", "titleSlug": "maximum-count-of-positive-integer-and-negative-integer", "content": "
Given an array nums sorted in non-decreasing order, return the maximum between the number of positive integers and the number of negative integers.
nums is pos and the number of negative integers is neg, then return the maximum of pos and neg.Note that 0 is neither positive nor negative.
\n
Example 1:
\n\n\nInput: nums = [-2,-1,-1,1,2,3]\nOutput: 3\nExplanation: There are 3 positive integers and 3 negative integers. The maximum count among them is 3.\n\n\n
Example 2:
\n\n\nInput: nums = [-3,-2,-1,0,0,1,2]\nOutput: 3\nExplanation: There are 2 positive integers and 3 negative integers. The maximum count among them is 3.\n\n\n
Example 3:
\n\n\nInput: nums = [5,20,66,1314]\nOutput: 4\nExplanation: There are 4 positive integers and 0 negative integers. The maximum count among them is 4.\n\n\n
\n
Constraints:
\n\n1 <= nums.length <= 2000-2000 <= nums[i] <= 2000nums is sorted in a non-decreasing order.\n
Follow up: Can you solve the problem in O(log(n)) time complexity?
给你一个按 非递减顺序 排列的数组 nums ,返回正整数数目和负整数数目中的最大值。
nums 中正整数的数目是 pos ,而负整数的数目是 neg ,返回 pos 和 neg二者中的最大值。注意:0 既不是正整数也不是负整数。
\n\n
示例 1:
\n\n\n输入:nums = [-2,-1,-1,1,2,3]\n输出:3\n解释:共有 3 个正整数和 3 个负整数。计数得到的最大值是 3 。\n\n\n
示例 2:
\n\n\n输入:nums = [-3,-2,-1,0,0,1,2]\n输出:3\n解释:共有 2 个正整数和 3 个负整数。计数得到的最大值是 3 。\n\n\n
示例 3:
\n\n\n输入:nums = [5,20,66,1314]\n输出:4\n解释:共有 4 个正整数和 0 个负整数。计数得到的最大值是 4 。\n\n\n
\n\n
提示:
\n\n1 <= nums.length <= 2000-2000 <= nums[i] <= 2000nums 按 非递减顺序 排列。\n\n
进阶:你可以设计并实现时间复杂度为 O(log(n)) 的算法解决此问题吗?
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