The bitwise AND of an array nums is the bitwise AND of all integers in nums.
nums = [1, 5, 3], the bitwise AND is equal to 1 & 5 & 3 = 1.nums = [7], the bitwise AND is 7.You are given an array of positive integers candidates. Compute the bitwise AND for all possible combinations of elements in the candidates array.
Return the size of the largest combination of candidates with a bitwise AND greater than 0.
\n
Example 1:
\n\n\nInput: candidates = [16,17,71,62,12,24,14]\nOutput: 4\nExplanation: The combination [16,17,62,24] has a bitwise AND of 16 & 17 & 62 & 24 = 16 > 0.\nThe size of the combination is 4.\nIt can be shown that no combination with a size greater than 4 has a bitwise AND greater than 0.\nNote that more than one combination may have the largest size.\nFor example, the combination [62,12,24,14] has a bitwise AND of 62 & 12 & 24 & 14 = 8 > 0.\n\n\n
Example 2:
\n\n\nInput: candidates = [8,8]\nOutput: 2\nExplanation: The largest combination [8,8] has a bitwise AND of 8 & 8 = 8 > 0.\nThe size of the combination is 2, so we return 2.\n\n\n
\n
Constraints:
\n\n1 <= candidates.length <= 1051 <= candidates[i] <= 107对数组 nums 执行 按位与 相当于对数组 nums 中的所有整数执行 按位与 。
nums = [1, 5, 3] 来说，按位与等于 1 & 5 & 3 = 1 。nums = [7] 而言，按位与等于 7 。给你一个正整数数组 candidates 。计算 candidates 中的数字每种组合下 按位与 的结果。
返回按位与结果大于 0 的 最长 组合的长度。
\n\n
示例 1：
\n\n\n输入：candidates = [16,17,71,62,12,24,14]\n输出：4\n解释：组合 [16,17,62,24] 的按位与结果是 16 & 17 & 62 & 24 = 16 > 0 。\n组合长度是 4 。\n可以证明不存在按位与结果大于 0 且长度大于 4 的组合。\n注意，符合长度最大的组合可能不止一种。\n例如，组合 [62,12,24,14] 的按位与结果是 62 & 12 & 24 & 14 = 8 > 0 。\n\n\n
示例 2：
\n\n\n输入：candidates = [8,8]\n输出：2\n解释：最长组合是 [8,8] ，按位与结果 8 & 8 = 8 > 0 。\n组合长度是 2 ，所以返回 2 。\n\n\n
\n\n
提示：
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