You are given an array of integers nums. You are also given an integer original which is the first number that needs to be searched for in nums.
You then do the following steps:
\n\noriginal is found in nums, multiply it by two (i.e., set original = 2 * original).Return the final value of original.
\n
Example 1:
\n\n\nInput: nums = [5,3,6,1,12], original = 3\nOutput: 24\nExplanation: \n- 3 is found in nums. 3 is multiplied by 2 to obtain 6.\n- 6 is found in nums. 6 is multiplied by 2 to obtain 12.\n- 12 is found in nums. 12 is multiplied by 2 to obtain 24.\n- 24 is not found in nums. Thus, 24 is returned.\n\n\n
Example 2:
\n\n\nInput: nums = [2,7,9], original = 4\nOutput: 4\nExplanation:\n- 4 is not found in nums. Thus, 4 is returned.\n\n\n
\n
Constraints:
\n\n1 <= nums.length <= 10001 <= nums[i], original <= 1000给你一个整数数组 nums ，另给你一个整数 original ，这是需要在 nums 中搜索的第一个数字。
接下来，你需要按下述步骤操作：
\n\nnums 中找到 original ，将 original 乘以 2 ，得到新 original（即，令 original = 2 * original）。original ，就对新 original 继续 重复 这一过程。返回 original 的 最终 值。
\n\n
示例 1：
\n\n\n输入：nums = [5,3,6,1,12], original = 3\n输出：24\n解释： \n- 3 能在 nums 中找到。3 * 2 = 6 。\n- 6 能在 nums 中找到。6 * 2 = 12 。\n- 12 能在 nums 中找到。12 * 2 = 24 。\n- 24 不能在 nums 中找到。因此，返回 24 。\n\n\n
示例 2：
\n\n\n输入：nums = [2,7,9], original = 4\n输出：4\n解释：\n- 4 不能在 nums 中找到。因此，返回 4 。\n\n\n
\n\n
提示：
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