You are given an array of non-overlapping intervals intervals where intervals[i] = [starti, endi] represent the start and the end of the ith interval and intervals is sorted in ascending order by starti. You are also given an interval newInterval = [start, end] that represents the start and end of another interval.
Insert newInterval into intervals such that intervals is still sorted in ascending order by starti and intervals still does not have any overlapping intervals (merge overlapping intervals if necessary).
Return intervals after the insertion.
Note that you don't need to modify intervals in-place. You can make a new array and return it.
\n
Example 1:
\n\n\nInput: intervals = [[1,3],[6,9]], newInterval = [2,5]\nOutput: [[1,5],[6,9]]\n\n\n
Example 2:
\n\n\nInput: intervals = [[1,2],[3,5],[6,7],[8,10],[12,16]], newInterval = [4,8]\nOutput: [[1,2],[3,10],[12,16]]\nExplanation: Because the new interval [4,8] overlaps with [3,5],[6,7],[8,10].\n\n\n
\n
Constraints:
\n\n0 <= intervals.length <= 104intervals[i].length == 20 <= starti <= endi <= 105intervals is sorted by starti in ascending order.newInterval.length == 20 <= start <= end <= 105给你一个 无重叠的 ，按照区间起始端点排序的区间列表 intervals，其中 intervals[i] = [starti, endi] 表示第 i 个区间的开始和结束，并且 intervals 按照 starti 升序排列。同样给定一个区间 newInterval = [start, end] 表示另一个区间的开始和结束。
在 intervals 中插入区间 newInterval，使得 intervals 依然按照 starti 升序排列，且区间之间不重叠（如果有必要的话，可以合并区间）。
返回插入之后的 intervals。
注意 你不需要原地修改 intervals。你可以创建一个新数组然后返回它。
\n\n
示例 1：
\n\n\n输入：intervals = [[1,3],[6,9]], newInterval = [2,5]\n输出：[[1,5],[6,9]]\n\n\n
示例 2：
\n\n\n输入：intervals = [[1,2],[3,5],[6,7],[8,10],[12,16]], newInterval = [4,8]\n输出：[[1,2],[3,10],[12,16]]\n解释：这是因为新的区间\n\n[4,8]与[3,5],[6,7],[8,10]重叠。\n
\n\n
提示：
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