{ "data": { "question": { "questionId": "381", "questionFrontendId": "381", "categoryTitle": "Algorithms", "boundTopicId": 1653, "title": "Insert Delete GetRandom O(1) - Duplicates allowed", "titleSlug": "insert-delete-getrandom-o1-duplicates-allowed", "content": "
RandomizedCollection is a data structure that contains a collection of numbers, possibly duplicates (i.e., a multiset). It should support inserting and removing specific elements and also reporting a random element.
Implement the RandomizedCollection class:
RandomizedCollection() Initializes the empty RandomizedCollection object.bool insert(int val) Inserts an item val into the multiset, even if the item is already present. Returns true if the item is not present, false otherwise.bool remove(int val) Removes an item val from the multiset if present. Returns true if the item is present, false otherwise. Note that if val has multiple occurrences in the multiset, we only remove one of them.int getRandom() Returns a random element from the current multiset of elements. The probability of each element being returned is linearly related to the number of the same values the multiset contains.You must implement the functions of the class such that each function works on average O(1) time complexity.
Note: The test cases are generated such that getRandom will only be called if there is at least one item in the RandomizedCollection.
\n
Example 1:
\n\n\nInput\n["RandomizedCollection", "insert", "insert", "insert", "getRandom", "remove", "getRandom"]\n[[], [1], [1], [2], [], [1], []]\nOutput\n[null, true, false, true, 2, true, 1]\n\nExplanation\nRandomizedCollection randomizedCollection = new RandomizedCollection();\nrandomizedCollection.insert(1); // return true since the collection does not contain 1.\n // Inserts 1 into the collection.\nrandomizedCollection.insert(1); // return false since the collection contains 1.\n // Inserts another 1 into the collection. Collection now contains [1,1].\nrandomizedCollection.insert(2); // return true since the collection does not contain 2.\n // Inserts 2 into the collection. Collection now contains [1,1,2].\nrandomizedCollection.getRandom(); // getRandom should:\n // - return 1 with probability 2/3, or\n // - return 2 with probability 1/3.\nrandomizedCollection.remove(1); // return true since the collection contains 1.\n // Removes 1 from the collection. Collection now contains [1,2].\nrandomizedCollection.getRandom(); // getRandom should return 1 or 2, both equally likely.\n\n\n
\n
Constraints:
\n\n-231 <= val <= 231 - 12 * 105 calls in total will be made to insert, remove, and getRandom.getRandom is called.RandomizedCollection 是一种包含数字集合(可能是重复的)的数据结构。它应该支持插入和删除特定元素,以及删除随机元素。
实现 RandomizedCollection 类:
RandomizedCollection()初始化空的 RandomizedCollection 对象。bool insert(int val) 将一个 val 项插入到集合中,即使该项已经存在。如果该项不存在,则返回 true ,否则返回 false 。bool remove(int val) 如果存在,从集合中移除一个 val 项。如果该项存在,则返回 true ,否则返回 false 。注意,如果 val 在集合中出现多次,我们只删除其中一个。int getRandom() 从当前的多个元素集合中返回一个随机元素。每个元素被返回的概率与集合中包含的相同值的数量 线性相关 。您必须实现类的函数,使每个函数的 平均 时间复杂度为 O(1) 。
注意:生成测试用例时,只有在 RandomizedCollection 中 至少有一项 时,才会调用 getRandom 。
\n\n
示例 1:
\n\n\n输入\n[\"RandomizedCollection\", \"insert\", \"insert\", \"insert\", \"getRandom\", \"remove\", \"getRandom\"]\n[[], [1], [1], [2], [], [1], []]\n输出\n[null, true, false, true, 2, true, 1]\n\n解释\nRandomizedCollection collection = new RandomizedCollection();// 初始化一个空的集合。\ncollection.insert(1); // 返回 true,因为集合不包含 1。\n // 将 1 插入到集合中。\ncollection.insert(1); // 返回 false,因为集合包含 1。\n // 将另一个 1 插入到集合中。集合现在包含 [1,1]。\ncollection.insert(2); // 返回 true,因为集合不包含 2。\n // 将 2 插入到集合中。集合现在包含 [1,1,2]。\ncollection.getRandom(); // getRandom 应当:\n // 有 2/3 的概率返回 1,\n // 1/3 的概率返回 2。\ncollection.remove(1); // 返回 true,因为集合包含 1。\n // 从集合中移除 1。集合现在包含 [1,2]。\ncollection.getRandom(); // getRandom 应该返回 1 或 2,两者的可能性相同。\n\n
\n\n
提示:
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