You have the four functions:
\n\nprintFizz that prints the word "fizz" to the console,printBuzz that prints the word "buzz" to the console,printFizzBuzz that prints the word "fizzbuzz" to the console, andprintNumber that prints a given integer to the console.You are given an instance of the class FizzBuzz that has four functions: fizz, buzz, fizzbuzz and number. The same instance of FizzBuzz will be passed to four different threads:
fizz() that should output the word "fizz".buzz() that should output the word "buzz".fizzbuzz() that should output the word "fizzbuzz".number() that should only output the integers.Modify the given class to output the series [1, 2, "fizz", 4, "buzz", ...] where the ith token (1-indexed) of the series is:
"fizzbuzz" if i is divisible by 3 and 5,"fizz" if i is divisible by 3 and not 5,"buzz" if i is divisible by 5 and not 3, ori if i is not divisible by 3 or 5.Implement the FizzBuzz class:
FizzBuzz(int n) Initializes the object with the number n that represents the length of the sequence that should be printed.void fizz(printFizz) Calls printFizz to output "fizz".void buzz(printBuzz) Calls printBuzz to output "buzz".void fizzbuzz(printFizzBuzz) Calls printFizzBuzz to output "fizzbuzz".void number(printNumber) Calls printnumber to output the numbers.\n
Example 1:
\nInput: n = 15\nOutput: [1,2,\"fizz\",4,\"buzz\",\"fizz\",7,8,\"fizz\",\"buzz\",11,\"fizz\",13,14,\"fizzbuzz\"]\n
Example 2:
\nInput: n = 5\nOutput: [1,2,\"fizz\",4,\"buzz\"]\n\n
\n
Constraints:
\n\n1 <= n <= 50编写一个可以从 1 到 n 输出代表这个数字的字符串的程序，但是：
\n\n例如，当 n = 15，输出： 1, 2, fizz, 4, buzz, fizz, 7, 8, fizz, buzz, 11, fizz, 13, 14, fizzbuzz。
假设有这么一个类：
\n\n\nclass FizzBuzz {\n public FizzBuzz(int n) { ... } // constructor\n public void fizz(printFizz) { ... } // only output \"fizz\"\n public void buzz(printBuzz) { ... } // only output \"buzz\"\n public void fizzbuzz(printFizzBuzz) { ... } // only output \"fizzbuzz\"\n public void number(printNumber) { ... } // only output the numbers\n}\n\n请你实现一个有四个线程的多线程版 FizzBuzz， 同一个 FizzBuzz 实例会被如下四个线程使用：
fizz() 来判断是否能被 3 整除，如果可以，则输出 fizz。buzz() 来判断是否能被 5 整除，如果可以，则输出 buzz。fizzbuzz() 来判断是否同时能被 3 和 5 整除，如果可以，则输出 fizzbuzz。number() 来实现输出既不能被 3 整除也不能被 5 整除的数字。\n\n
提示：
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