{ "data": { "question": { "questionId": "3776", "questionFrontendId": "3469", "categoryTitle": "Algorithms", "boundTopicId": 3590020, "title": "Find Minimum Cost to Remove Array Elements", "titleSlug": "find-minimum-cost-to-remove-array-elements", "content": "
You are given an integer array nums. Your task is to remove all elements from the array by performing one of the following operations at each step until nums is empty:
nums and remove them. The cost of this operation is the maximum of the two elements removed.nums, remove all the remaining elements in a single operation. The cost of this operation is the maximum of the remaining elements.Return the minimum cost required to remove all the elements.
\n\n\n
Example 1:
\n\nInput: nums = [6,2,8,4]
\n\nOutput: 12
\n\nExplanation:
\n\nInitially, nums = [6, 2, 8, 4].
nums[0] = 6 and nums[2] = 8 with a cost of max(6, 8) = 8. Now, nums = [2, 4].max(2, 4) = 4.The cost to remove all elements is 8 + 4 = 12. This is the minimum cost to remove all elements in nums. Hence, the output is 12.
Example 2:
\n\nInput: nums = [2,1,3,3]
\n\nOutput: 5
\n\nExplanation:
\n\nInitially, nums = [2, 1, 3, 3].
nums[0] = 2 and nums[1] = 1 with a cost of max(2, 1) = 2. Now, nums = [3, 3].max(3, 3) = 3.The cost to remove all elements is 2 + 3 = 5. This is the minimum cost to remove all elements in nums. Hence, the output is 5.
\n
Constraints:
\n\n1 <= nums.length <= 10001 <= nums[i] <= 106给你一个整数数组 nums。你的任务是在每一步中执行以下操作之一,直到 nums 为空,从而移除 所有元素 :
nums 的前三个元素中选择任意两个元素并移除它们。此操作的成本为移除的两个元素中的 最大值 。nums 中剩下的元素少于三个,则一次性移除所有剩余元素。此操作的成本为剩余元素中的 最大值 。返回移除所有元素所需的最小成本。
\n\n\n\n
示例 1
\n\n输入:nums = [6,2,8,4]
\n\n输出:12
\n\n解释:
\n\n初始时,nums = [6, 2, 8, 4]。
nums[0] = 6 和 nums[2] = 8,操作成本为 max(6, 8) = 8。现在,nums = [2, 4]。max(2, 4) = 4。移除所有元素的成本为 8 + 4 = 12。这是移除 nums 中所有元素的最小成本。所以输出 12。
示例 2
\n\n输入:nums = [2,1,3,3]
\n\n输出:5
\n\n解释:
\n\n初始时,nums = [2, 1, 3, 3]。
nums[0] = 2 和 nums[1] = 1,操作成本为 max(2, 1) = 2。现在,nums = [3, 3]。max(3, 3) = 3。移除所有元素的成本为 2 + 3 = 5。这是移除 nums 中所有元素的最小成本。因此,输出是 5。
\n\n
提示:
\n\n1 <= nums.length <= 10001 <= nums[i] <= 106dp[i][j], where i represents the last remaining element and j represents the starting index of the current prefix."
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