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            "questionId": "3181",
            "questionFrontendId": "2940",
            "categoryTitle": "Algorithms",
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            "title": "Find Building Where Alice and Bob Can Meet",
            "titleSlug": "find-building-where-alice-and-bob-can-meet",
            "content": "<p>You are given a <strong>0-indexed</strong> array <code>heights</code> of positive integers, where <code>heights[i]</code> represents the height of the <code>i<sup>th</sup></code> building.</p>\n\n<p>If a person is in building <code>i</code>, they can move to any other building <code>j</code> if and only if <code>i &lt; j</code> and <code>heights[i] &lt; heights[j]</code>.</p>\n\n<p>You are also given another array <code>queries</code> where <code>queries[i] = [a<sub>i</sub>, b<sub>i</sub>]</code>. On the <code>i<sup>th</sup></code> query, Alice is in building <code>a<sub>i</sub></code> while Bob is in building <code>b<sub>i</sub></code>.</p>\n\n<p>Return <em>an array</em> <code>ans</code> <em>where</em> <code>ans[i]</code> <em>is <strong>the index of the leftmost building</strong> where Alice and Bob can meet on the</em> <code>i<sup>th</sup></code> <em>query</em>. <em>If Alice and Bob cannot move to a common building on query</em> <code>i</code>, <em>set</em> <code>ans[i]</code> <em>to</em> <code>-1</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> heights = [6,4,8,5,2,7], queries = [[0,1],[0,3],[2,4],[3,4],[2,2]]\n<strong>Output:</strong> [2,5,-1,5,2]\n<strong>Explanation:</strong> In the first query, Alice and Bob can move to building 2 since heights[0] &lt; heights[2] and heights[1] &lt; heights[2]. \nIn the second query, Alice and Bob can move to building 5 since heights[0] &lt; heights[5] and heights[3] &lt; heights[5]. \nIn the third query, Alice cannot meet Bob since Alice cannot move to any other building.\nIn the fourth query, Alice and Bob can move to building 5 since heights[3] &lt; heights[5] and heights[4] &lt; heights[5].\nIn the fifth query, Alice and Bob are already in the same building.  \nFor ans[i] != -1, It can be shown that ans[i] is the leftmost building where Alice and Bob can meet.\nFor ans[i] == -1, It can be shown that there is no building where Alice and Bob can meet.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> heights = [5,3,8,2,6,1,4,6], queries = [[0,7],[3,5],[5,2],[3,0],[1,6]]\n<strong>Output:</strong> [7,6,-1,4,6]\n<strong>Explanation:</strong> In the first query, Alice can directly move to Bob&#39;s building since heights[0] &lt; heights[7].\nIn the second query, Alice and Bob can move to building 6 since heights[3] &lt; heights[6] and heights[5] &lt; heights[6].\nIn the third query, Alice cannot meet Bob since Bob cannot move to any other building.\nIn the fourth query, Alice and Bob can move to building 4 since heights[3] &lt; heights[4] and heights[0] &lt; heights[4].\nIn the fifth query, Alice can directly move to Bob&#39;s building since heights[1] &lt; heights[6].\nFor ans[i] != -1, It can be shown that ans[i] is the leftmost building where Alice and Bob can meet.\nFor ans[i] == -1, It can be shown that there is no building where Alice and Bob can meet.\n\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= heights.length &lt;= 5 * 10<sup>4</sup></code></li>\n\t<li><code>1 &lt;= heights[i] &lt;= 10<sup>9</sup></code></li>\n\t<li><code>1 &lt;= queries.length &lt;= 5 * 10<sup>4</sup></code></li>\n\t<li><code>queries[i] = [a<sub>i</sub>, b<sub>i</sub>]</code></li>\n\t<li><code>0 &lt;= a<sub>i</sub>, b<sub>i</sub> &lt;= heights.length - 1</code></li>\n</ul>\n",
            "translatedTitle": "找到 Alice 和 Bob 可以相遇的建筑",
            "translatedContent": "<p>给你一个下标从 <strong>0</strong>&nbsp;开始的正整数数组&nbsp;<code>heights</code>&nbsp;，其中&nbsp;<code>heights[i]</code>&nbsp;表示第 <code>i</code>&nbsp;栋建筑的高度。</p>\n\n<p>如果一个人在建筑&nbsp;<code>i</code>&nbsp;，且存在&nbsp;<code>i &lt; j</code>&nbsp;的建筑&nbsp;<code>j</code>&nbsp;满足&nbsp;<code>heights[i] &lt; heights[j]</code>&nbsp;，那么这个人可以移动到建筑&nbsp;<code>j</code>&nbsp;。</p>\n\n<p>给你另外一个数组&nbsp;<code>queries</code>&nbsp;，其中&nbsp;<code>queries[i] = [a<sub>i</sub>, b<sub>i</sub>]</code>&nbsp;。第&nbsp;<code>i</code>&nbsp;个查询中，Alice 在建筑&nbsp;<code>a<sub>i</sub></code> ，Bob 在建筑&nbsp;<code>b<sub>i</sub></code><sub>&nbsp;</sub>。</p>\n\n<p>请你能返回一个数组&nbsp;<code>ans</code>&nbsp;，其中&nbsp;<code>ans[i]</code>&nbsp;是第&nbsp;<code>i</code>&nbsp;个查询中，Alice 和 Bob 可以相遇的&nbsp;<strong>最左边的建筑</strong>&nbsp;。如果对于查询&nbsp;<code>i</code>&nbsp;，Alice<em> </em>和<em> </em>Bob 不能相遇，令&nbsp;<code>ans[i]</code> 为&nbsp;<code>-1</code>&nbsp;。</p>\n\n<p>&nbsp;</p>\n\n<p><strong class=\"example\">示例 1：</strong></p>\n\n<pre>\n<b>输入：</b>heights = [6,4,8,5,2,7], queries = [[0,1],[0,3],[2,4],[3,4],[2,2]]\n<b>输出：</b>[2,5,-1,5,2]\n<b>解释：</b>第一个查询中，Alice 和 Bob 可以移动到建筑 2 ，因为 heights[0] &lt; heights[2] 且 heights[1] &lt; heights[2] 。\n第二个查询中，Alice 和 Bob 可以移动到建筑 5 ，因为 heights[0] &lt; heights[5] 且 heights[3] &lt; heights[5] 。\n第三个查询中，Alice 无法与 Bob 相遇，因为 Alice 不能移动到任何其他建筑。\n第四个查询中，Alice 和 Bob 可以移动到建筑 5 ，因为 heights[3] &lt; heights[5] 且 heights[4] &lt; heights[5] 。\n第五个查询中，Alice 和 Bob 已经在同一栋建筑中。\n对于 ans[i] != -1 ，ans[i] 是 Alice 和 Bob 可以相遇的建筑中最左边建筑的下标。\n对于 ans[i] == -1 ，不存在 Alice 和 Bob 可以相遇的建筑。\n</pre>\n\n<p><strong class=\"example\">示例 2：</strong></p>\n\n<pre>\n<b>输入：</b>heights = [5,3,8,2,6,1,4,6], queries = [[0,7],[3,5],[5,2],[3,0],[1,6]]\n<b>输出：</b>[7,6,-1,4,6]\n<strong>解释：</strong>第一个查询中，Alice 可以直接移动到 Bob 的建筑，因为 heights[0] &lt; heights[7] 。\n第二个查询中，Alice 和 Bob 可以移动到建筑 6 ，因为 heights[3] &lt; heights[6] 且 heights[5] &lt; heights[6] 。\n第三个查询中，Alice 无法与 Bob 相遇，因为 Bob 不能移动到任何其他建筑。\n第四个查询中，Alice 和 Bob 可以移动到建筑 4 ，因为 heights[3] &lt; heights[4] 且 heights[0] &lt; heights[4] 。\n第五个查询中，Alice 可以直接移动到 Bob 的建筑，因为 heights[1] &lt; heights[6] 。\n对于 ans[i] != -1 ，ans[i] 是 Alice 和 Bob 可以相遇的建筑中最左边建筑的下标。\n对于 ans[i] == -1 ，不存在 Alice 和 Bob 可以相遇的建筑。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= heights.length &lt;= 5 * 10<sup>4</sup></code></li>\n\t<li><code>1 &lt;= heights[i] &lt;= 10<sup>9</sup></code></li>\n\t<li><code>1 &lt;= queries.length &lt;= 5 * 10<sup>4</sup></code></li>\n\t<li><code>queries[i] = [a<sub>i</sub>, b<sub>i</sub>]</code></li>\n\t<li><code>0 &lt;= a<sub>i</sub>, b<sub>i</sub> &lt;= heights.length - 1</code></li>\n</ul>\n",
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                "For each query <code>[x, y]</code>, if <code>x == y</code> or <code>heights[x] < heights[y]</code>, then the answer is <code>y</code> since <code>x ≤ y</code>.",
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<code>use-after-free<\\/code> \\u9519\\u8bef\\u3002<\\/p>\\r\\n\\r\\n<p>\\u4e3a\\u4e86\\u4f7f\\u7528\\u65b9\\u4fbf\\uff0c\\u5927\\u90e8\\u5206\\u6807\\u51c6\\u5e93\\u7684\\u5934\\u6587\\u4ef6\\u5df2\\u7ecf\\u88ab\\u81ea\\u52a8\\u5bfc\\u5165\\u3002<\\/p>\\r\\n\\r\\n<p>\\u5982\\u60f3\\u4f7f\\u7528\\u54c8\\u5e0c\\u8868\\u8fd0\\u7b97, \\u60a8\\u53ef\\u4ee5\\u4f7f\\u7528 <a href=\\\"https:\\/\\/troydhanson.github.io\\/uthash\\/\\\" target=\\\"_blank\\\">uthash<\\/a>\\u3002 \\\"uthash.h\\\"\\u5df2\\u7ecf\\u9ed8\\u8ba4\\u88ab\\u5bfc\\u5165\\u3002\\u8bf7\\u770b\\u5982\\u4e0b\\u793a\\u4f8b:<\\/p>\\r\\n\\r\\n<p><b>1. \\u5f80\\u54c8\\u5e0c\\u8868\\u4e2d\\u6dfb\\u52a0\\u4e00\\u4e2a\\u5bf9\\u8c61\\uff1a<\\/b>\\r\\n<pre>\\r\\nstruct hash_entry {\\r\\n    int id;            \\/* we'll use this field as the key *\\/\\r\\n    char name[10];\\r\\n    UT_hash_handle hh; \\/* makes this structure hashable *\\/\\r\\n};\\r\\n\\r\\nstruct hash_entry *users = NULL;\\r\\n\\r\\nvoid add_user(struct hash_entry 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