Two strings are considered close if you can attain one from the other using the following operations:
\n\nabcde -> aecdbaacabb -> bbcbaa (all a's turn into b's, and all b's turn into a's)You can use the operations on either string as many times as necessary.
\n\nGiven two strings, word1 and word2, return true if word1 and word2 are close, and false otherwise.
\n
Example 1:
\n\n\nInput: word1 = "abc", word2 = "bca"\nOutput: true\nExplanation: You can attain word2 from word1 in 2 operations.\nApply Operation 1: "abc" -> "acb"\nApply Operation 1: "acb" -> "bca"\n\n\n
Example 2:
\n\n\nInput: word1 = "a", word2 = "aa"\nOutput: false\nExplanation: It is impossible to attain word2 from word1, or vice versa, in any number of operations.\n\n\n
Example 3:
\n\n\nInput: word1 = "cabbba", word2 = "abbccc"\nOutput: true\nExplanation: You can attain word2 from word1 in 3 operations.\nApply Operation 1: "cabbba" -> "caabbb"\nApply Operation 2: "caabbb" -> "baaccc"\nApply Operation 2: "baaccc" -> "abbccc"\n\n\n
\n
Constraints:
\n\n1 <= word1.length, word2.length <= 105word1 and word2 contain only lowercase English letters.如果可以使用以下操作从一个字符串得到另一个字符串，则认为两个字符串 接近 ：
\n\nabcde -> aecdbaacabb -> bbcbaa（所有 a 转化为 b ，而所有的 b 转换为 a ）你可以根据需要对任意一个字符串多次使用这两种操作。
\n\n给你两个字符串，word1 和 word2 。如果 word1 和 word2 接近 ，就返回 true ；否则，返回 false 。
\n\n
示例 1：
\n\n\n输入：word1 = \"abc\", word2 = \"bca\"\n输出：true\n解释：2 次操作从 word1 获得 word2 。\n执行操作 1：\"abc\" -> \"acb\"\n执行操作 1：\"acb\" -> \"bca\"\n\n\n
示例 2：
\n\n\n输入：word1 = \"a\", word2 = \"aa\"\n输出：false\n解释：不管执行多少次操作，都无法从 word1 得到 word2 ，反之亦然。\n\n
示例 3：
\n\n\n输入：word1 = \"cabbba\", word2 = \"abbccc\"\n输出：true\n解释：3 次操作从 word1 获得 word2 。\n执行操作 1：\"cabbba\" -> \"caabbb\"\n执行操作 2：\"caabbb\" -> \"baaccc\"\n执行操作 2：\"baaccc\" -> \"abbccc\"\n\n\n提示：
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"style": "LEETCODE",
"exampleTestcases": "\"abc\"\n\"bca\"\n\"a\"\n\"aa\"\n\"cabbba\"\n\"abbccc\"",
"__typename": "QuestionNode"
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