{ "data": { "question": { "questionId": "3516", "questionFrontendId": "3242", "categoryTitle": "Algorithms", "boundTopicId": 2866988, "title": "Design Neighbor Sum Service", "titleSlug": "design-neighbor-sum-service", "content": "
You are given a n x n 2D array grid containing distinct elements in the range [0, n2 - 1].
Implement the NeighborSum class:
NeighborSum(int [][]grid) initializes the object.int adjacentSum(int value) returns the sum of elements which are adjacent neighbors of value, that is either to the top, left, right, or bottom of value in grid.int diagonalSum(int value) returns the sum of elements which are diagonal neighbors of value, that is either to the top-left, top-right, bottom-left, or bottom-right of value in grid.
\n
Example 1:
\n\nInput:
\n\n["NeighborSum", "adjacentSum", "adjacentSum", "diagonalSum", "diagonalSum"]
\n\n[[[[0, 1, 2], [3, 4, 5], [6, 7, 8]]], [1], [4], [4], [8]]
\n\nOutput: [null, 6, 16, 16, 4]
\n\nExplanation:
\n\n
Example 2:
\n\nInput:
\n\n["NeighborSum", "adjacentSum", "diagonalSum"]
\n\n[[[[1, 2, 0, 3], [4, 7, 15, 6], [8, 9, 10, 11], [12, 13, 14, 5]]], [15], [9]]
\n\nOutput: [null, 23, 45]
\n\nExplanation:
\n\n
\n
Constraints:
\n\n3 <= n == grid.length == grid[0].length <= 100 <= grid[i][j] <= n2 - 1grid[i][j] are distinct.value in adjacentSum and diagonalSum will be in the range [0, n2 - 1].2 * n2 calls will be made to adjacentSum and diagonalSum.给你一个 n x n 的二维数组 grid,它包含范围 [0, n2 - 1] 内的不重复元素。
实现 neighborSum 类:
neighborSum(int [][]grid) 初始化对象。int adjacentSum(int value) 返回在 grid 中与 value 相邻的元素之和,相邻指的是与 value 在上、左、右或下的元素。int diagonalSum(int value) 返回在 grid 中与 value 对角线相邻的元素之和,对角线相邻指的是与 value 在左上、右上、左下或右下的元素。
\n\n
示例 1:
\n\n输入:
\n\n[\"neighborSum\", \"adjacentSum\", \"adjacentSum\", \"diagonalSum\", \"diagonalSum\"]
\n\n[[[[0, 1, 2], [3, 4, 5], [6, 7, 8]]], [1], [4], [4], [8]]
\n\n输出: [null, 6, 16, 16, 4]
\n\n解释:
\n\n
示例 2:
\n\n输入:
\n\n[\"neighborSum\", \"adjacentSum\", \"diagonalSum\"]
\n\n[[[[1, 2, 0, 3], [4, 7, 15, 6], [8, 9, 10, 11], [12, 13, 14, 5]]], [15], [9]]
\n\n输出: [null, 23, 45]
\n\n解释:
\n\n
\n\n
提示:
\n\n3 <= n == grid.length == grid[0].length <= 100 <= grid[i][j] <= n2 - 1grid[i][j] 值均不重复。adjacentSum 和 diagonalSum 中的 value 均在范围 [0, n2 - 1] 内。adjacentSum 和 diagonalSum 总共 2 * n2 次。(i, j) in which the element is present.",
"You can store the coordinates for each value."
],
"solution": null,
"status": null,
"sampleTestCase": "[\"NeighborSum\",\"adjacentSum\",\"adjacentSum\",\"diagonalSum\",\"diagonalSum\"]\n[[[[0,1,2],[3,4,5],[6,7,8]]],[1],[4],[4],[8]]",
"metaData": "{\n \"classname\": \"NeighborSum\",\n \"constructor\": {\n \"params\": [\n {\n \"type\": \"integer[][]\",\n \"name\": \"grid\"\n }\n ]\n },\n \"methods\": [\n {\n \"params\": [\n {\n \"type\": \"integer\",\n \"name\": \"value\"\n }\n ],\n \"name\": \"adjacentSum\",\n \"return\": {\n \"type\": \"integer\"\n }\n },\n {\n \"params\": [\n {\n \"type\": \"integer\",\n \"name\": \"value\"\n }\n ],\n \"name\": \"diagonalSum\",\n \"return\": {\n \"type\": \"integer\"\n }\n }\n ],\n \"return\": {\n \"type\": \"boolean\"\n },\n \"systemdesign\": true\n}",
"judgerAvailable": true,
"judgeType": "large",
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