You are given an integer array nums and an integer k. Your task is to partition nums into one or more non-empty contiguous segments such that in each segment, the difference between its maximum and minimum elements is at most k.
Return the total number of ways to partition nums under this condition.
Since the answer may be too large, return it modulo 109 + 7.
\n
Example 1:
\n\nInput: nums = [9,4,1,3,7], k = 4
\n\nOutput: 6
\n\nExplanation:
\n\nThere are 6 valid partitions where the difference between the maximum and minimum elements in each segment is at most k = 4:
[[9], [4], [1], [3], [7]][[9], [4], [1], [3, 7]][[9], [4], [1, 3], [7]][[9], [4, 1], [3], [7]][[9], [4, 1], [3, 7]][[9], [4, 1, 3], [7]]Example 2:
\n\nInput: nums = [3,3,4], k = 0
\n\nOutput: 2
\n\nExplanation:
\n\nThere are 2 valid partitions that satisfy the given conditions:
\n\n[[3], [3], [4]][[3, 3], [4]]\n
Constraints:
\n\n2 <= nums.length <= 5 * 1041 <= nums[i] <= 1090 <= k <= 109给你一个整数数组 nums 和一个整数 k。你的任务是将 nums 分割成一个或多个 非空 的连续子段，使得每个子段的 最大值 与 最小值 之间的差值 不超过 k。
返回在此条件下将 nums 分割的总方法数。
由于答案可能非常大，返回结果需要对 109 + 7 取余数。
\n\n
示例 1：
\n\n输入： nums = [9,4,1,3,7], k = 4
\n\n输出： 6
\n\n解释：
\n\n共有 6 种有效的分割方式，使得每个子段中的最大值与最小值之差不超过 k = 4：
[[9], [4], [1], [3], [7]][[9], [4], [1], [3, 7]][[9], [4], [1, 3], [7]][[9], [4, 1], [3], [7]][[9], [4, 1], [3, 7]][[9], [4, 1, 3], [7]]示例 2：
\n\n输入： nums = [3,3,4], k = 0
\n\n输出： 2
\n\n解释：
\n\n共有 2 种有效的分割方式，满足给定条件：
\n\n[[3], [3], [4]][[3, 3], [4]]\n\n
提示：
\n\n2 <= nums.length <= 5 * 1041 <= nums[i] <= 1090 <= k <= 109dp[idx] be the count of ways to partition the array with the last partition ending at index idx.",
"Try using a sliding window; we can track the minimum and maximum in the window using deques."
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