{ "data": { "question": { "questionId": "2605", "questionFrontendId": "2514", "categoryTitle": "Algorithms", "boundTopicId": 2029982, "title": "Count Anagrams", "titleSlug": "count-anagrams", "content": "
You are given a string s containing one or more words. Every consecutive pair of words is separated by a single space ' '.
A string t is an anagram of string s if the ith word of t is a permutation of the ith word of s.
"acb dfe" is an anagram of "abc def", but "def cab" and "adc bef" are not.Return the number of distinct anagrams of s. Since the answer may be very large, return it modulo 109 + 7.
\n
Example 1:
\n\n\nInput: s = "too hot"\nOutput: 18\nExplanation: Some of the anagrams of the given string are "too hot", "oot hot", "oto toh", "too toh", and "too oht".\n\n\n
Example 2:
\n\n\nInput: s = "aa"\nOutput: 1\nExplanation: There is only one anagram possible for the given string.\n\n
\n
Constraints:
\n\n1 <= s.length <= 105s consists of lowercase English letters and spaces ' '.给你一个字符串 s ,它包含一个或者多个单词。单词之间用单个空格 ' ' 隔开。
如果字符串 t 中第 i 个单词是 s 中第 i 个单词的一个 排列 ,那么我们称字符串 t 是字符串 s 的同位异构字符串。
\"acb dfe\" 是 \"abc def\" 的同位异构字符串,但是 \"def cab\" 和 \"adc bef\" 不是。请你返回 s 的同位异构字符串的数目,由于答案可能很大,请你将它对 109 + 7 取余 后返回。
\n\n
示例 1:
\n\n输入:s = \"too hot\"\n输出:18\n解释:输入字符串的一些同位异构字符串为 \"too hot\" ,\"oot hot\" ,\"oto toh\" ,\"too toh\" 以及 \"too oht\" 。\n\n\n
示例 2:
\n\n输入:s = \"aa\"\n输出:1\n解释:输入字符串只有一个同位异构字符串。\n\n
\n\n
提示:
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