{ "data": { "question": { "questionId": "165", "questionFrontendId": "165", "categoryTitle": "Algorithms", "boundTopicId": 1849, "title": "Compare Version Numbers", "titleSlug": "compare-version-numbers", "content": "
Given two version strings, version1 and version2, compare them. A version string consists of revisions separated by dots '.'. The value of the revision is its integer conversion ignoring leading zeros.
To compare version strings, compare their revision values in left-to-right order. If one of the version strings has fewer revisions, treat the missing revision values as 0.
Return the following:
\n\nversion1 < version2, return -1.version1 > version2, return 1.\n
Example 1:
\n\nInput: version1 = "1.2", version2 = "1.10"
\n\nOutput: -1
\n\nExplanation:
\n\nversion1's second revision is "2" and version2's second revision is "10": 2 < 10, so version1 < version2.
\nExample 2:
\n\nInput: version1 = "1.01", version2 = "1.001"
\n\nOutput: 0
\n\nExplanation:
\n\nIgnoring leading zeroes, both "01" and "001" represent the same integer "1".
\nExample 3:
\n\nInput: version1 = "1.0", version2 = "1.0.0.0"
\n\nOutput: 0
\n\nExplanation:
\n\nversion1 has less revisions, which means every missing revision are treated as "0".
\n\n
Constraints:
\n\n1 <= version1.length, version2.length <= 500version1 and version2 only contain digits and '.'.version1 and version2 are valid version numbers.version1 and version2 can be stored in a 32-bit integer.给你两个 版本号字符串 version1 和 version2 ,请你比较它们。版本号由被点 '.' 分开的修订号组成。修订号的值 是它 转换为整数 并忽略前导零。
比较版本号时,请按 从左到右的顺序 依次比较它们的修订号。如果其中一个版本字符串的修订号较少,则将缺失的修订号视为 0。
返回规则如下:
\n\nversion1 < version2 返回 -1,version1 > version2 返回 1,0。\n\n
示例 1:
\n\n输入:version1 = \"1.2\", version2 = \"1.10\"
\n\n输出:-1
\n\n解释:
\n\nversion1 的第二个修订号为 \"2\",version2 的第二个修订号为 \"10\":2 < 10,所以 version1 < version2。
\n示例 2:
\n\n输入:version1 = \"1.01\", version2 = \"1.001\"
\n\n输出:0
\n\n解释:
\n\n忽略前导零,\"01\" 和 \"001\" 都代表相同的整数 \"1\"。
\n示例 3:
\n\n输入:version1 = \"1.0\", version2 = \"1.0.0.0\"
\n\n输出:0
\n\n解释:
\n\nversion1 有更少的修订号,每个缺失的修订号按 \"0\" 处理。
\n\n\n
提示:
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"exampleTestcases": "\"1.2\"\n\"1.10\"\n\"1.01\"\n\"1.001\"\n\"1.0\"\n\"1.0.0.0\"",
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