![\"\"](\"https://assets.leetcode.com/uploads/2020/02/14/cinema_seats_1.png\")
A cinema has n rows of seats, numbered from 1 to n and there are ten seats in each row, labelled from 1 to 10 as shown in the figure above.
Given the array reservedSeats containing the numbers of seats already reserved, for example, reservedSeats[i] = [3,8] means the seat located in row 3 and labelled with 8 is already reserved.
Return the maximum number of four-person groups you can assign on the cinema seats. A four-person group occupies four adjacent seats in one single row. Seats across an aisle (such as [3,3] and [3,4]) are not considered to be adjacent, but there is an exceptional case on which an aisle split a four-person group, in that case, the aisle split a four-person group in the middle, which means to have two people on each side.
\n\n\n
Example 1:
\n\n![\"\"](\"https://assets.leetcode.com/uploads/2020/02/14/cinema_seats_3.png\")
\nInput: n = 3, reservedSeats = [[1,2],[1,3],[1,8],[2,6],[3,1],[3,10]]\nOutput: 4\nExplanation: The figure above shows the optimal allocation for four groups, where seats mark with blue are already reserved and contiguous seats mark with orange are for one group.\n\n\n
Example 2:
\n\n\nInput: n = 2, reservedSeats = [[2,1],[1,8],[2,6]]\nOutput: 2\n\n\n
Example 3:
\n\n\nInput: n = 4, reservedSeats = [[4,3],[1,4],[4,6],[1,7]]\nOutput: 4\n\n\n
\n
Constraints:
\n\n1 <= n <= 10^91 <= reservedSeats.length <= min(10*n, 10^4)reservedSeats[i].length == 21 <= reservedSeats[i][0] <= n1 <= reservedSeats[i][1] <= 10reservedSeats[i] are distinct.![\"\"](\"https://assets.leetcode-cn.com/aliyun-lc-upload/uploads/2020/03/21/cinema_seats_1.png\")
如上图所示，电影院的观影厅中有 n 行座位，行编号从 1 到 n ，且每一行内总共有 10 个座位，列编号从 1 到 10 。
给你数组 reservedSeats ，包含所有已经被预约了的座位。比如说，reservedSeats[i]=[3,8] ，它表示第 3 行第 8 个座位被预约了。
请你返回 最多能安排多少个 4 人家庭 。4 人家庭要占据 同一行内连续 的 4 个座位。隔着过道的座位（比方说 [3,3] 和 [3,4]）不是连续的座位，但是如果你可以将 4 人家庭拆成过道两边各坐 2 人，这样子是允许的。
\n\n\n\n
示例 1：
\n\n![\"\"](\"https://assets.leetcode-cn.com/aliyun-lc-upload/uploads/2020/03/21/cinema_seats_3.png\")
\n输入：n = 3, reservedSeats = [[1,2],[1,3],[1,8],[2,6],[3,1],[3,10]]\n输出：4\n解释：上图所示是最优的安排方案，总共可以安排 4 个家庭。蓝色的叉表示被预约的座位，橙色的连续座位表示一个 4 人家庭。\n\n\n
示例 2：
\n\n\n输入：n = 2, reservedSeats = [[2,1],[1,8],[2,6]]\n输出：2\n\n\n
示例 3：
\n\n\n输入：n = 4, reservedSeats = [[4,3],[1,4],[4,6],[1,7]]\n输出：4\n\n\n
\n\n
提示：
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