{ "data": { "question": { "questionId": "2010", "questionFrontendId": "1880", "categoryTitle": "Algorithms", "boundTopicId": 797235, "title": "Check if Word Equals Summation of Two Words", "titleSlug": "check-if-word-equals-summation-of-two-words", "content": "
The letter value of a letter is its position in the alphabet starting from 0 (i.e. 'a' -> 0, 'b' -> 1, 'c' -> 2, etc.).
The numerical value of some string of lowercase English letters s is the concatenation of the letter values of each letter in s, which is then converted into an integer.
s = "acb", we concatenate each letter's letter value, resulting in "021". After converting it, we get 21.You are given three strings firstWord, secondWord, and targetWord, each consisting of lowercase English letters 'a' through 'j' inclusive.
Return true if the summation of the numerical values of firstWord and secondWord equals the numerical value of targetWord, or false otherwise.
\n
Example 1:
\n\n\nInput: firstWord = "acb", secondWord = "cba", targetWord = "cdb"\nOutput: true\nExplanation:\nThe numerical value of firstWord is "acb" -> "021" -> 21.\nThe numerical value of secondWord is "cba" -> "210" -> 210.\nThe numerical value of targetWord is "cdb" -> "231" -> 231.\nWe return true because 21 + 210 == 231.\n\n\n
Example 2:
\n\n\nInput: firstWord = "aaa", secondWord = "a", targetWord = "aab"\nOutput: false\nExplanation: \nThe numerical value of firstWord is "aaa" -> "000" -> 0.\nThe numerical value of secondWord is "a" -> "0" -> 0.\nThe numerical value of targetWord is "aab" -> "001" -> 1.\nWe return false because 0 + 0 != 1.\n\n\n
Example 3:
\n\n\nInput: firstWord = "aaa", secondWord = "a", targetWord = "aaaa"\nOutput: true\nExplanation: \nThe numerical value of firstWord is "aaa" -> "000" -> 0.\nThe numerical value of secondWord is "a" -> "0" -> 0.\nThe numerical value of targetWord is "aaaa" -> "0000" -> 0.\nWe return true because 0 + 0 == 0.\n\n\n
\n
Constraints:
\n\n1 <= firstWord.length, secondWord.length, targetWord.length <= 8firstWord, secondWord, and targetWord consist of lowercase English letters from 'a' to 'j' inclusive.字母的 字母值 取决于字母在字母表中的位置,从 0 开始 计数。即,'a' -> 0、'b' -> 1、'c' -> 2,以此类推。
对某个由小写字母组成的字符串 s 而言,其 数值 就等于将 s 中每个字母的 字母值 按顺序 连接 并 转换 成对应整数。
s = \"acb\" ,依次连接每个字母的字母值可以得到 \"021\" ,转换为整数得到 21 。给你三个字符串 firstWord、secondWord 和 targetWord ,每个字符串都由从 'a' 到 'j' (含 'a' 和 'j' )的小写英文字母组成。
如果 firstWord 和 secondWord 的 数值之和 等于 targetWord 的数值,返回 true ;否则,返回 false 。
\n\n
示例 1:
\n\n输入:firstWord = \"acb\", secondWord = \"cba\", targetWord = \"cdb\"\n输出:true\n解释:\nfirstWord 的数值为 \"acb\" -> \"021\" -> 21\nsecondWord 的数值为 \"cba\" -> \"210\" -> 210\ntargetWord 的数值为 \"cdb\" -> \"231\" -> 231\n由于 21 + 210 == 231 ,返回 true\n\n\n
示例 2:
\n\n输入:firstWord = \"aaa\", secondWord = \"a\", targetWord = \"aab\"\n输出:false\n解释:\nfirstWord 的数值为 \"aaa\" -> \"000\" -> 0\nsecondWord 的数值为 \"a\" -> \"0\" -> 0\ntargetWord 的数值为 \"aab\" -> \"001\" -> 1\n由于 0 + 0 != 1 ,返回 false\n\n
示例 3:
\n\n输入:firstWord = \"aaa\", secondWord = \"a\", targetWord = \"aaaa\"\n输出:true\n解释:\nfirstWord 的数值为 \"aaa\" -> \"000\" -> 0\nsecondWord 的数值为 \"a\" -> \"0\" -> 0\ntargetWord 的数值为 \"aaaa\" -> \"0000\" -> 0\n由于 0 + 0 == 0 ,返回 true\n\n\n
\n\n
提示:
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