{ "data": { "question": { "questionId": "3636", "questionFrontendId": "3340", "categoryTitle": "Algorithms", "boundTopicId": 2974471, "title": "Check Balanced String", "titleSlug": "check-balanced-string", "content": "
You are given a string num consisting of only digits. A string of digits is called balanced if the sum of the digits at even indices is equal to the sum of digits at odd indices.
Return true if num is balanced, otherwise return false.
\n
Example 1:
\n\nInput: num = "1234"
\n\nOutput: false
\n\nExplanation:
\n\n1 + 3 == 4, and the sum of digits at odd indices is 2 + 4 == 6.num is not balanced.Example 2:
\n\nInput: num = "24123"
\n\nOutput: true
\n\nExplanation:
\n\n2 + 1 + 3 == 6, and the sum of digits at odd indices is 4 + 2 == 6.num is balanced.\n
Constraints:
\n\n2 <= num.length <= 100num consists of digits only给你一个仅由数字 0 - 9 组成的字符串 num。如果偶数下标处的数字之和等于奇数下标处的数字之和,则认为该数字字符串是一个 平衡字符串。
如果 num 是一个 平衡字符串,则返回 true;否则,返回 false。
\n\n
示例 1:
\n\n输入:num = \"1234\"
\n\n输出:false
\n\n解释:
\n\n1 + 3 = 4,奇数下标处的数字之和为 2 + 4 = 6。num 不是平衡字符串。示例 2:
\n\n输入:num = \"24123\"
\n\n输出:true
\n\n解释:
\n\n2 + 1 + 3 = 6,奇数下标处的数字之和为 4 + 2 = 6。num 是平衡字符串。\n\n
提示:
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"style": "LEETCODE",
"exampleTestcases": "\"1234\"\n\"24123\"",
"__typename": "QuestionNode"
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