You are given an array routes representing bus routes where routes[i] is a bus route that the ith bus repeats forever.
routes[0] = [1, 5, 7], this means that the 0th bus travels in the sequence 1 -> 5 -> 7 -> 1 -> 5 -> 7 -> 1 -> ... forever.You will start at the bus stop source (You are not on any bus initially), and you want to go to the bus stop target. You can travel between bus stops by buses only.
Return the least number of buses you must take to travel from source to target. Return -1 if it is not possible.
\n
Example 1:
\n\n\nInput: routes = [[1,2,7],[3,6,7]], source = 1, target = 6\nOutput: 2\nExplanation: The best strategy is take the first bus to the bus stop 7, then take the second bus to the bus stop 6.\n\n\n
Example 2:
\n\n\nInput: routes = [[7,12],[4,5,15],[6],[15,19],[9,12,13]], source = 15, target = 12\nOutput: -1\n\n\n
\n\n
\n
Constraints:
\n\n1 <= routes.length <= 500.1 <= routes[i].length <= 105routes[i] are unique.sum(routes[i].length) <= 1050 <= routes[i][j] < 1060 <= source, target < 106给你一个数组 routes ，表示一系列公交线路，其中每个 routes[i] 表示一条公交线路，第 i 辆公交车将会在上面循环行驶。
routes[0] = [1, 5, 7] 表示第 0 辆公交车会一直按序列 1 -> 5 -> 7 -> 1 -> 5 -> 7 -> 1 -> ... 这样的车站路线行驶。现在从 source 车站出发（初始时不在公交车上），要前往 target 车站。 期间仅可乘坐公交车。
求出 最少乘坐的公交车数量 。如果不可能到达终点车站，返回 -1 。
\n\n
示例 1：
\n\n\n输入：routes = [[1,2,7],[3,6,7]], source = 1, target = 6\n输出：2\n解释：最优策略是先乘坐第一辆公交车到达车站 7 , 然后换乘第二辆公交车到车站 6 。 \n\n\n
示例 2：
\n\n\n输入：routes = [[7,12],[4,5,15],[6],[15,19],[9,12,13]], source = 15, target = 12\n输出：-1\n\n\n
\n\n
提示：
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