{ "data": { "question": { "questionId": "432", "questionFrontendId": "432", "categoryTitle": "Algorithms", "boundTopicId": 1900, "title": "All O`one Data Structure", "titleSlug": "all-oone-data-structure", "content": "
Design a data structure to store the strings' count with the ability to return the strings with minimum and maximum counts.
\n\nImplement the AllOne class:
AllOne() Initializes the object of the data structure.inc(String key) Increments the count of the string key by 1. If key does not exist in the data structure, insert it with count 1.dec(String key) Decrements the count of the string key by 1. If the count of key is 0 after the decrement, remove it from the data structure. It is guaranteed that key exists in the data structure before the decrement.getMaxKey() Returns one of the keys with the maximal count. If no element exists, return an empty string "".getMinKey() Returns one of the keys with the minimum count. If no element exists, return an empty string "".Note that each function must run in O(1) average time complexity.
\n
Example 1:
\n\n\nInput\n["AllOne", "inc", "inc", "getMaxKey", "getMinKey", "inc", "getMaxKey", "getMinKey"]\n[[], ["hello"], ["hello"], [], [], ["leet"], [], []]\nOutput\n[null, null, null, "hello", "hello", null, "hello", "leet"]\n\nExplanation\nAllOne allOne = new AllOne();\nallOne.inc("hello");\nallOne.inc("hello");\nallOne.getMaxKey(); // return "hello"\nallOne.getMinKey(); // return "hello"\nallOne.inc("leet");\nallOne.getMaxKey(); // return "hello"\nallOne.getMinKey(); // return "leet"\n\n\n\n
Constraints:
\n\n1 <= key.length <= 10key consists of lowercase English letters.dec, key is existing in the data structure.5 * 104 calls will be made to inc, dec, getMaxKey, and getMinKey.请你设计一个用于存储字符串计数的数据结构,并能够返回计数最小和最大的字符串。
\n\n实现 AllOne 类:
AllOne() 初始化数据结构的对象。inc(String key) 字符串 key 的计数增加 1 。如果数据结构中尚不存在 key ,那么插入计数为 1 的 key 。dec(String key) 字符串 key 的计数减少 1 。如果 key 的计数在减少后为 0 ,那么需要将这个 key 从数据结构中删除。测试用例保证:在减少计数前,key 存在于数据结构中。getMaxKey() 返回任意一个计数最大的字符串。如果没有元素存在,返回一个空字符串 \"\" 。getMinKey() 返回任意一个计数最小的字符串。如果没有元素存在,返回一个空字符串 \"\" 。注意:每个函数都应当满足 O(1) 平均时间复杂度。
\n\n
示例:
\n\n\n输入\n[\"AllOne\", \"inc\", \"inc\", \"getMaxKey\", \"getMinKey\", \"inc\", \"getMaxKey\", \"getMinKey\"]\n[[], [\"hello\"], [\"hello\"], [], [], [\"leet\"], [], []]\n输出\n[null, null, null, \"hello\", \"hello\", null, \"hello\", \"leet\"]\n\n解释\nAllOne allOne = new AllOne();\nallOne.inc(\"hello\");\nallOne.inc(\"hello\");\nallOne.getMaxKey(); // 返回 \"hello\"\nallOne.getMinKey(); // 返回 \"hello\"\nallOne.inc(\"leet\");\nallOne.getMaxKey(); // 返回 \"hello\"\nallOne.getMinKey(); // 返回 \"leet\"\n\n\n
\n\n
提示:
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