You are given a string s consisting of lowercase English letters, an integer t representing the number of transformations to perform, and an array nums of size 26. In one transformation, every character in s is replaced according to the following rules:
s[i] with the next nums[s[i] - 'a'] consecutive characters in the alphabet. For example, if s[i] = 'a' and nums[0] = 3, the character 'a' transforms into the next 3 consecutive characters ahead of it, which results in "bcd".'z'. For example, if s[i] = 'y' and nums[24] = 3, the character 'y' transforms into the next 3 consecutive characters ahead of it, which results in "zab".Return the length of the resulting string after exactly t transformations.
Since the answer may be very large, return it modulo 109 + 7.
\n
Example 1:
\n\nInput: s = "abcyy", t = 2, nums = [1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,2]
\n\nOutput: 7
\n\nExplanation:
\n\nFirst Transformation (t = 1):
\n\n\t'a' becomes 'b' as nums[0] == 1'b' becomes 'c' as nums[1] == 1'c' becomes 'd' as nums[2] == 1'y' becomes 'z' as nums[24] == 1'y' becomes 'z' as nums[24] == 1"bcdzz"Second Transformation (t = 2):
\n\n\t'b' becomes 'c' as nums[1] == 1'c' becomes 'd' as nums[2] == 1'd' becomes 'e' as nums[3] == 1'z' becomes 'ab' as nums[25] == 2'z' becomes 'ab' as nums[25] == 2"cdeabab"Final Length of the string: The string is "cdeabab", which has 7 characters.
Example 2:
\n\nInput: s = "azbk", t = 1, nums = [2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2]
\n\nOutput: 8
\n\nExplanation:
\n\nFirst Transformation (t = 1):
\n\n\t'a' becomes 'bc' as nums[0] == 2'z' becomes 'ab' as nums[25] == 2'b' becomes 'cd' as nums[1] == 2'k' becomes 'lm' as nums[10] == 2"bcabcdlm"Final Length of the string: The string is "bcabcdlm", which has 8 characters.
\n
Constraints:
\n\n1 <= s.length <= 105s consists only of lowercase English letters.1 <= t <= 109nums.length == 261 <= nums[i] <= 25Compiled with clang 17 using the latest C++ 23 standard, and libstdc++ provided by GCC 13.
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