{ "data": { "question": { "questionId": "2380", "questionFrontendId": "2286", "categoryTitle": "Algorithms", "boundTopicId": 1518390, "title": "Booking Concert Tickets in Groups", "titleSlug": "booking-concert-tickets-in-groups", "content": "
A concert hall has n rows numbered from 0 to n - 1, each with m seats, numbered from 0 to m - 1. You need to design a ticketing system that can allocate seats in the following cases:
k spectators can sit together in a row.k spectators can get a seat. They may or may not sit together.Note that the spectators are very picky. Hence:
\n\nmaxRow. maxRow can vary from group to group.Implement the BookMyShow class:
BookMyShow(int n, int m) Initializes the object with n as number of rows and m as number of seats per row.int[] gather(int k, int maxRow) Returns an array of length 2 denoting the row and seat number (respectively) of the first seat being allocated to the k members of the group, who must sit together. In other words, it returns the smallest possible r and c such that all [c, c + k - 1] seats are valid and empty in row r, and r <= maxRow. Returns [] in case it is not possible to allocate seats to the group.boolean scatter(int k, int maxRow) Returns true if all k members of the group can be allocated seats in rows 0 to maxRow, who may or may not sit together. If the seats can be allocated, it allocates k seats to the group with the smallest row numbers, and the smallest possible seat numbers in each row. Otherwise, returns false.\n
Example 1:
\n\n\nInput\n["BookMyShow", "gather", "gather", "scatter", "scatter"]\n[[2, 5], [4, 0], [2, 0], [5, 1], [5, 1]]\nOutput\n[null, [0, 0], [], true, false]\n\nExplanation\nBookMyShow bms = new BookMyShow(2, 5); // There are 2 rows with 5 seats each \nbms.gather(4, 0); // return [0, 0]\n // The group books seats [0, 3] of row 0. \nbms.gather(2, 0); // return []\n // There is only 1 seat left in row 0,\n // so it is not possible to book 2 consecutive seats. \nbms.scatter(5, 1); // return True\n // The group books seat 4 of row 0 and seats [0, 3] of row 1. \nbms.scatter(5, 1); // return False\n // There is only one seat left in the hall.\n\n\n
\n
Constraints:
\n\n1 <= n <= 5 * 1041 <= m, k <= 1090 <= maxRow <= n - 15 * 104 calls in total will be made to gather and scatter.一个音乐会总共有 n 排座位,编号从 0 到 n - 1 ,每一排有 m 个座椅,编号为 0 到 m - 1 。你需要设计一个买票系统,针对以下情况进行座位安排:
k 位观众坐在 同一排座位,且座位连续 。k 位观众中 每一位 都有座位坐,但他们 不一定 坐在一起。由于观众非常挑剔,所以:
\n\nmaxRow ,这个组才能订座位。每一组的 maxRow 可能 不同 。请你实现 BookMyShow 类:
BookMyShow(int n, int m) ,初始化对象,n 是排数,m 是每一排的座位数。int[] gather(int k, int maxRow) 返回长度为 2 的数组,表示 k 个成员中 第一个座位 的排数和座位编号,这 k 位成员必须坐在 同一排座位,且座位连续 。换言之,返回最小可能的 r 和 c 满足第 r 排中 [c, c + k - 1] 的座位都是空的,且 r <= maxRow 。如果 无法 安排座位,返回 [] 。boolean scatter(int k, int maxRow) 如果组里所有 k 个成员 不一定 要坐在一起的前提下,都能在第 0 排到第 maxRow 排之间找到座位,那么请返回 true 。这种情况下,每个成员都优先找排数 最小 ,然后是座位编号最小的座位。如果不能安排所有 k 个成员的座位,请返回 false 。\n\n
示例 1:
\n\n\n输入:\n[\"BookMyShow\", \"gather\", \"gather\", \"scatter\", \"scatter\"]\n[[2, 5], [4, 0], [2, 0], [5, 1], [5, 1]]\n输出:\n[null, [0, 0], [], true, false]\n\n解释:\nBookMyShow bms = new BookMyShow(2, 5); // 总共有 2 排,每排 5 个座位。\nbms.gather(4, 0); // 返回 [0, 0]\n // 这一组安排第 0 排 [0, 3] 的座位。\nbms.gather(2, 0); // 返回 []\n // 第 0 排只剩下 1 个座位。\n // 所以无法安排 2 个连续座位。\nbms.scatter(5, 1); // 返回 True\n // 这一组安排第 0 排第 4 个座位和第 1 排 [0, 3] 的座位。\nbms.scatter(5, 1); // 返回 False\n // 总共只剩下 2 个座位。\n\n\n
\n\n
提示:
\n\n1 <= n <= 5 * 1041 <= m, k <= 1090 <= maxRow <= n - 1gather 和 scatter 总 调用次数不超过 5 * 104 次。\\u7248\\u672c\\uff1a \\u7f16\\u8bd1\\u65f6\\uff0c\\u5c06\\u4f1a\\u91c7\\u7528 \\u4e3a\\u4e86\\u4f7f\\u7528\\u65b9\\u4fbf\\uff0c\\u5927\\u90e8\\u5206\\u6807\\u51c6\\u5e93\\u7684\\u5934\\u6587\\u4ef6\\u5df2\\u7ecf\\u88ab\\u81ea\\u52a8\\u5bfc\\u5165\\u3002<\\/p>\"],\"java\":[\"Java\",\" \\u7248\\u672c\\uff1a \\u4e3a\\u4e86\\u65b9\\u4fbf\\u8d77\\u89c1\\uff0c\\u5927\\u90e8\\u5206\\u6807\\u51c6\\u5e93\\u7684\\u5934\\u6587\\u4ef6\\u5df2\\u88ab\\u5bfc\\u5165\\u3002<\\/p>\\r\\n\\r\\n \\u5305\\u542b Pair \\u7c7b: https:\\/\\/docs.oracle.com\\/javase\\/8\\/javafx\\/api\\/javafx\\/util\\/Pair.html <\\/p>\"],\"python\":[\"Python\",\" \\u7248\\u672c\\uff1a \\u4e3a\\u4e86\\u65b9\\u4fbf\\u8d77\\u89c1\\uff0c\\u5927\\u90e8\\u5206\\u5e38\\u7528\\u5e93\\u5df2\\u7ecf\\u88ab\\u81ea\\u52a8 \\u5bfc\\u5165\\uff0c\\u5982\\uff1aarray<\\/a>, bisect<\\/a>, 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