{ "data": { "question": { "questionId": "284", "questionFrontendId": "284", "categoryTitle": "Algorithms", "boundTopicId": 1880, "title": "Peeking Iterator", "titleSlug": "peeking-iterator", "content": "
Design an iterator that supports the peek
operation on an existing iterator in addition to the hasNext
and the next
operations.
Implement the PeekingIterator
class:
PeekingIterator(Iterator<int> nums)
Initializes the object with the given integer iterator iterator
.int next()
Returns the next element in the array and moves the pointer to the next element.boolean hasNext()
Returns true
if there are still elements in the array.int peek()
Returns the next element in the array without moving the pointer.Note: Each language may have a different implementation of the constructor and Iterator
, but they all support the int next()
and boolean hasNext()
functions.
\n
Example 1:
\n\n\nInput\n["PeekingIterator", "next", "peek", "next", "next", "hasNext"]\n[[[1, 2, 3]], [], [], [], [], []]\nOutput\n[null, 1, 2, 2, 3, false]\n\nExplanation\nPeekingIterator peekingIterator = new PeekingIterator([1, 2, 3]); // [1,2,3]\npeekingIterator.next(); // return 1, the pointer moves to the next element [1,2,3].\npeekingIterator.peek(); // return 2, the pointer does not move [1,2,3].\npeekingIterator.next(); // return 2, the pointer moves to the next element [1,2,3]\npeekingIterator.next(); // return 3, the pointer moves to the next element [1,2,3]\npeekingIterator.hasNext(); // return False\n\n\n
\n
Constraints:
\n\n1 <= nums.length <= 1000
1 <= nums[i] <= 1000
next
and peek
are valid.1000
calls will be made to next
, hasNext
, and peek
.\nFollow up: How would you extend your design to be generic and work with all types, not just integer?", "translatedTitle": "顶端迭代器", "translatedContent": "
请你在设计一个迭代器,在集成现有迭代器拥有的 hasNext
和 next
操作的基础上,还额外支持 peek
操作。
实现 PeekingIterator
类:
PeekingIterator(Iterator<int> nums)
使用指定整数迭代器 nums
初始化迭代器。int next()
返回数组中的下一个元素,并将指针移动到下个元素处。bool hasNext()
如果数组中存在下一个元素,返回 true
;否则,返回 false
。int peek()
返回数组中的下一个元素,但 不 移动指针。注意:每种语言可能有不同的构造函数和迭代器 Iterator
,但均支持 int next()
和 boolean hasNext()
函数。
\n\n
示例 1:
\n\n\n输入:\n[\"PeekingIterator\", \"next\", \"peek\", \"next\", \"next\", \"hasNext\"]\n[[[1, 2, 3]], [], [], [], [], []]\n输出:\n[null, 1, 2, 2, 3, false]\n\n解释:\nPeekingIterator peekingIterator = new PeekingIterator([1, 2, 3]); // [1,2,3]\npeekingIterator.next(); // 返回 1 ,指针移动到下一个元素 [1,2,3]\npeekingIterator.peek(); // 返回 2 ,指针未发生移动 [1,2,3]\npeekingIterator.next(); // 返回 2 ,指针移动到下一个元素 [1,2,3]\npeekingIterator.next(); // 返回 3 ,指针移动到下一个元素 [1,2,3]\npeekingIterator.hasNext(); // 返回 False\n\n\n
\n\n
提示:
\n\n1 <= nums.length <= 1000
1 <= nums[i] <= 1000
next
和 peek
的调用均有效next
、hasNext
和 peek
最多调用 1000
次\n\n
进阶:你将如何拓展你的设计?使之变得通用化,从而适应所有的类型,而不只是整数型?
\n", "isPaidOnly": false, "difficulty": "Medium", "likes": 157, "dislikes": 0, "isLiked": null, "similarQuestions": "[{\"title\": \"Binary Search Tree Iterator\", \"titleSlug\": \"binary-search-tree-iterator\", \"difficulty\": \"Medium\", \"translatedTitle\": \"\\u4e8c\\u53c9\\u641c\\u7d22\\u6811\\u8fed\\u4ee3\\u5668\"}, {\"title\": \"Flatten 2D Vector\", \"titleSlug\": \"flatten-2d-vector\", \"difficulty\": \"Medium\", \"translatedTitle\": \"\\u5c55\\u5f00\\u4e8c\\u7ef4\\u5411\\u91cf\"}, {\"title\": \"Zigzag Iterator\", \"titleSlug\": \"zigzag-iterator\", \"difficulty\": \"Medium\", \"translatedTitle\": \"\\u952f\\u9f7f\\u8fed\\u4ee3\\u5668\"}]", "contributors": [], "langToValidPlayground": "{\"cpp\": false, \"java\": true, \"python\": true, \"python3\": false, \"mysql\": false, \"mssql\": false, \"oraclesql\": false, \"c\": false, \"csharp\": false, \"javascript\": false, \"ruby\": false, \"bash\": false, \"swift\": false, \"golang\": false, \"scala\": false, \"html\": false, \"pythonml\": false, \"kotlin\": false, \"rust\": false, \"php\": false, \"typescript\": false, \"racket\": false, \"erlang\": false, \"elixir\": false}", "topicTags": [ { "name": "Design", "slug": "design", "translatedName": "设计", "__typename": "TopicTagNode" }, { "name": "Array", "slug": "array", "translatedName": "数组", "__typename": "TopicTagNode" }, { "name": "Iterator", "slug": "iterator", "translatedName": "迭代器", "__typename": "TopicTagNode" } ], "companyTagStats": null, "codeSnippets": [ { "lang": "C++", "langSlug": "cpp", "code": "/*\n * Below is the interface for Iterator, which is already defined for you.\n * **DO NOT** modify the interface for Iterator.\n *\n * class Iterator {\n *\t\tstruct Data;\n * \t\tData* data;\n * public:\n *\t\tIterator(const vectorpeek()
before next()
vs next()
before peek()
.",
"For a clean implementation, check out Google's guava library source code."
],
"solution": null,
"status": null,
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