{ "data": { "question": { "questionId": "1381", "questionFrontendId": "1255", "categoryTitle": "Algorithms", "boundTopicId": 41145, "title": "Maximum Score Words Formed by Letters", "titleSlug": "maximum-score-words-formed-by-letters", "content": "
Given a list of words
, list of single letters
(might be repeating) and score
of every character.
Return the maximum score of any valid set of words formed by using the given letters (words[i]
cannot be used two or more times).
It is not necessary to use all characters in letters
and each letter can only be used once. Score of letters 'a'
, 'b'
, 'c'
, ... ,'z'
is given by score[0]
, score[1]
, ... , score[25]
respectively.
\n
Example 1:
\n\n\nInput: words = ["dog","cat","dad","good"], letters = ["a","a","c","d","d","d","g","o","o"], score = [1,0,9,5,0,0,3,0,0,0,0,0,0,0,2,0,0,0,0,0,0,0,0,0,0,0]\nOutput: 23\nExplanation:\nScore a=1, c=9, d=5, g=3, o=2\nGiven letters, we can form the words "dad" (5+1+5) and "good" (3+2+2+5) with a score of 23.\nWords "dad" and "dog" only get a score of 21.\n\n
Example 2:
\n\n\nInput: words = ["xxxz","ax","bx","cx"], letters = ["z","a","b","c","x","x","x"], score = [4,4,4,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,5,0,10]\nOutput: 27\nExplanation:\nScore a=4, b=4, c=4, x=5, z=10\nGiven letters, we can form the words "ax" (4+5), "bx" (4+5) and "cx" (4+5) with a score of 27.\nWord "xxxz" only get a score of 25.\n\n
Example 3:
\n\n\nInput: words = ["leetcode"], letters = ["l","e","t","c","o","d"], score = [0,0,1,1,1,0,0,0,0,0,0,1,0,0,1,0,0,0,0,1,0,0,0,0,0,0]\nOutput: 0\nExplanation:\nLetter "e" can only be used once.\n\n
\n
Constraints:
\n\n1 <= words.length <= 14
1 <= words[i].length <= 15
1 <= letters.length <= 100
letters[i].length == 1
score.length == 26
0 <= score[i] <= 10
words[i]
, letters[i]
contains only lower case English letters.你将会得到一份单词表 words
,一个字母表 letters
(可能会有重复字母),以及每个字母对应的得分情况表 score
。
请你帮忙计算玩家在单词拼写游戏中所能获得的「最高得分」:能够由 letters
里的字母拼写出的 任意 属于 words
单词子集中,分数最高的单词集合的得分。
单词拼写游戏的规则概述如下:
\n\nletters
里的字母来拼写单词表 words
中的单词。letters
中的部分字母,但是每个字母最多被使用一次。words
中每个单词只能计分(使用)一次。score
,字母 'a'
, 'b'
, 'c'
, ... , 'z'
对应的得分分别为 score[0]
, score[1]
, ..., score[25]
。\n\n
示例 1:
\n\n输入:words = ["dog","cat","dad","good"], letters = ["a","a","c","d","d","d","g","o","o"], score = [1,0,9,5,0,0,3,0,0,0,0,0,0,0,2,0,0,0,0,0,0,0,0,0,0,0]\n输出:23\n解释:\n字母得分为 a=1, c=9, d=5, g=3, o=2\n使用给定的字母表 letters,我们可以拼写单词 "dad" (5+1+5)和 "good" (3+2+2+5),得分为 23 。\n而单词 "dad" 和 "dog" 只能得到 21 分。\n\n
示例 2:
\n\n输入:words = ["xxxz","ax","bx","cx"], letters = ["z","a","b","c","x","x","x"], score = [4,4,4,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,5,0,10]\n输出:27\n解释:\n字母得分为 a=4, b=4, c=4, x=5, z=10\n使用给定的字母表 letters,我们可以组成单词 "ax" (4+5), "bx" (4+5) 和 "cx" (4+5) ,总得分为 27 。\n单词 "xxxz" 的得分仅为 25 。\n\n
示例 3:
\n\n输入:words = ["leetcode"], letters = ["l","e","t","c","o","d"], score = [0,0,1,1,1,0,0,0,0,0,0,1,0,0,1,0,0,0,0,1,0,0,0,0,0,0]\n输出:0\n解释:\n字母 "e" 在字母表 letters 中只出现了一次,所以无法组成单词表 words 中的单词。\n\n
\n\n
提示:
\n\n1 <= words.length <= 14
1 <= words[i].length <= 15
1 <= letters.length <= 100
letters[i].length == 1
score.length == 26
0 <= score[i] <= 10
words[i]
和 letters[i]
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