{ "data": { "question": { "questionId": "1896", "questionFrontendId": "1770", "categoryTitle": "Algorithms", "boundTopicId": 609228, "title": "Maximum Score from Performing Multiplication Operations", "titleSlug": "maximum-score-from-performing-multiplication-operations", "content": "
You are given two integer arrays nums
and multipliers
of size n
and m
respectively, where n >= m
. The arrays are 1-indexed.
You begin with a score of 0
. You want to perform exactly m
operations. On the ith
operation (1-indexed), you will:
x
from either the start or the end of the array nums
.multipliers[i] * x
to your score.x
from the array nums
.Return the maximum score after performing m
operations.
\n
Example 1:
\n\n\nInput: nums = [1,2,3], multipliers = [3,2,1]\nOutput: 14\nExplanation: An optimal solution is as follows:\n- Choose from the end, [1,2,3], adding 3 * 3 = 9 to the score.\n- Choose from the end, [1,2], adding 2 * 2 = 4 to the score.\n- Choose from the end, [1], adding 1 * 1 = 1 to the score.\nThe total score is 9 + 4 + 1 = 14.\n\n
Example 2:
\n\n\nInput: nums = [-5,-3,-3,-2,7,1], multipliers = [-10,-5,3,4,6]\nOutput: 102\nExplanation: An optimal solution is as follows:\n- Choose from the start, [-5,-3,-3,-2,7,1], adding -5 * -10 = 50 to the score.\n- Choose from the start, [-3,-3,-2,7,1], adding -3 * -5 = 15 to the score.\n- Choose from the start, [-3,-2,7,1], adding -3 * 3 = -9 to the score.\n- Choose from the end, [-2,7,1], adding 1 * 4 = 4 to the score.\n- Choose from the end, [-2,7], adding 7 * 6 = 42 to the score. \nThe total score is 50 + 15 - 9 + 4 + 42 = 102.\n\n\n
\n
Constraints:
\n\nn == nums.length
m == multipliers.length
1 <= m <= 103
m <= n <= 105
-1000 <= nums[i], multipliers[i] <= 1000
给你两个长度分别 n
和 m
的整数数组 nums
和 multipliers
,其中 n >= m
,数组下标 从 1 开始 计数。
初始时,你的分数为 0
。你需要执行恰好 m
步操作。在第 i
步操作(从 1 开始 计数)中,需要:
nums
开头处或者末尾处 的整数 x
。multipliers[i] * x
分,并累加到你的分数中。x
从数组 nums
中移除。在执行 m
步操作后,返回 最大 分数。
\n\n
示例 1:
\n\n输入:nums = [1,2,3], multipliers = [3,2,1]\n输出:14\n解释:一种最优解决方案如下:\n- 选择末尾处的整数 3 ,[1,2,3] ,得 3 * 3 = 9 分,累加到分数中。\n- 选择末尾处的整数 2 ,[1,2] ,得 2 * 2 = 4 分,累加到分数中。\n- 选择末尾处的整数 1 ,[1] ,得 1 * 1 = 1 分,累加到分数中。\n总分数为 9 + 4 + 1 = 14 。\n\n
示例 2:
\n\n输入:nums = [-5,-3,-3,-2,7,1], multipliers = [-10,-5,3,4,6]\n输出:102\n解释:一种最优解决方案如下:\n- 选择开头处的整数 -5 ,[-5,-3,-3,-2,7,1] ,得 -5 * -10 = 50 分,累加到分数中。\n- 选择开头处的整数 -3 ,[-3,-3,-2,7,1] ,得 -3 * -5 = 15 分,累加到分数中。\n- 选择开头处的整数 -3 ,[-3,-2,7,1] ,得 -3 * 3 = -9 分,累加到分数中。\n- 选择末尾处的整数 1 ,[-2,7,1] ,得 1 * 4 = 4 分,累加到分数中。\n- 选择末尾处的整数 7 ,[-2,7] ,得 7 * 6 = 42 分,累加到分数中。\n总分数为 50 + 15 - 9 + 4 + 42 = 102 。\n\n\n
\n\n
提示:
\n\nn == nums.length
m == multipliers.length
1 <= m <= 103
m <= n <= 105
-1000 <= nums[i], multipliers[i] <= 1000
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