{ "data": { "question": { "questionId": "38", "questionFrontendId": "38", "categoryTitle": "Algorithms", "boundTopicId": 978, "title": "Count and Say", "titleSlug": "count-and-say", "content": "
The count-and-say sequence is a sequence of digit strings defined by the recursive formula:
\n\ncountAndSay(1) = "1"
countAndSay(n)
is the way you would "say" the digit string from countAndSay(n-1)
, which is then converted into a different digit string.To determine how you "say" a digit string, split it into the minimal number of groups so that each group is a contiguous section all of the same character. Then for each group, say the number of characters, then say the character. To convert the saying into a digit string, replace the counts with a number and concatenate every saying.
\n\nFor example, the saying and conversion for digit string "3322251"
:
Given a positive integer n
, return the nth
term of the count-and-say sequence.
\n
Example 1:
\n\n\nInput: n = 1\nOutput: "1"\nExplanation: This is the base case.\n\n\n
Example 2:
\n\n\nInput: n = 4\nOutput: "1211"\nExplanation:\ncountAndSay(1) = "1"\ncountAndSay(2) = say "1" = one 1 = "11"\ncountAndSay(3) = say "11" = two 1's = "21"\ncountAndSay(4) = say "21" = one 2 + one 1 = "12" + "11" = "1211"\n\n\n
\n
Constraints:
\n\n1 <= n <= 30
给定一个正整数 n
,输出外观数列的第 n
项。
「外观数列」是一个整数序列,从数字 1 开始,序列中的每一项都是对前一项的描述。
\n\n你可以将其视作是由递归公式定义的数字字符串序列:
\n\ncountAndSay(1) = \"1\"
countAndSay(n)
是对 countAndSay(n-1)
的描述,然后转换成另一个数字字符串。前五项如下:
\n\n\n1. 1\n2. 11\n3. 21\n4. 1211\n5. 111221\n第一项是数字 1 \n描述前一项,这个数是\n\n1
即 “ 一 个 1 ”,记作\"11\"\n
描述前一项,这个数是11
即 “ 二 个 1 ” ,记作\"21\"\n
描述前一项,这个数是21
即 “ 一 个 2 + 一 个 1 ” ,记作 \"1211\"\n
描述前一项,这个数是1211
即 “ 一 个 1 + 一 个 2 + 二 个 1 ” ,记作 \"111221\"
\n
要 描述 一个数字字符串,首先要将字符串分割为 最小 数量的组,每个组都由连续的最多 相同字符 组成。然后对于每个组,先描述字符的数量,然后描述字符,形成一个描述组。要将描述转换为数字字符串,先将每组中的字符数量用数字替换,再将所有描述组连接起来。
\n\n例如,数字字符串 \"3322251\"
的描述如下图:
\n\n
示例 1:
\n\n\n输入:n = 1\n输出:\"1\"\n解释:这是一个基本样例。\n\n\n
示例 2:
\n\n\n输入:n = 4\n输出:\"1211\"\n解释:\ncountAndSay(1) = \"1\"\ncountAndSay(2) = 读 \"1\" = 一 个 1 = \"11\"\ncountAndSay(3) = 读 \"11\" = 二 个 1 = \"21\"\ncountAndSay(4) = 读 \"21\" = 一 个 2 + 一 个 1 = \"12\" + \"11\" = \"1211\"\n\n\n
\n\n
提示:
\n\n1 <= n <= 30
\r\n 1. 1\r\n 2. 11\r\n 3. 21\r\n 4. 1211\r\n 5. 111221 \r\n 6. 312211\r\n 7. 13112221\r\n 8. 1113213211\r\n 9. 31131211131221\r\n10. 13211311123113112211\r\n", "To generate the nth term, just count and say the n-1th term." ], "solution": null, "status": null, "sampleTestCase": "1", "metaData": "{\r\n \"name\": \"countAndSay\",\r\n \"params\": [\r\n {\r\n \"name\": \"n\",\r\n \"type\": \"integer\"\r\n }\r\n ],\r\n \"return\": {\r\n \"type\": \"string\"\r\n }\r\n}", "judgerAvailable": true, "judgeType": "large", "mysqlSchemas": [], "enableRunCode": true, "envInfo": "{\"cpp\":[\"C++\",\"
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