<p>Given an integer array <code>nums</code>, handle multiple queries of the following types:</p> <ol> <li><strong>Update</strong> the value of an element in <code>nums</code>.</li> <li>Calculate the <strong>sum</strong> of the elements of <code>nums</code> between indices <code>left</code> and <code>right</code> <strong>inclusive</strong> where <code>left <= right</code>.</li> </ol> <p>Implement the <code>NumArray</code> class:</p> <ul> <li><code>NumArray(int[] nums)</code> Initializes the object with the integer array <code>nums</code>.</li> <li><code>void update(int index, int val)</code> <strong>Updates</strong> the value of <code>nums[index]</code> to be <code>val</code>.</li> <li><code>int sumRange(int left, int right)</code> Returns the <strong>sum</strong> of the elements of <code>nums</code> between indices <code>left</code> and <code>right</code> <strong>inclusive</strong> (i.e. <code>nums[left] + nums[left + 1] + ... + nums[right]</code>).</li> </ul> <p> </p> <p><strong>Example 1:</strong></p> <pre> <strong>Input</strong> ["NumArray", "sumRange", "update", "sumRange"] [[[1, 3, 5]], [0, 2], [1, 2], [0, 2]] <strong>Output</strong> [null, 9, null, 8] <strong>Explanation</strong> NumArray numArray = new NumArray([1, 3, 5]); numArray.sumRange(0, 2); // return 1 + 3 + 5 = 9 numArray.update(1, 2); // nums = [1, 2, 5] numArray.sumRange(0, 2); // return 1 + 2 + 5 = 8 </pre> <p> </p> <p><strong>Constraints:</strong></p> <ul> <li><code>1 <= nums.length <= 3 * 10<sup>4</sup></code></li> <li><code>-100 <= nums[i] <= 100</code></li> <li><code>0 <= index < nums.length</code></li> <li><code>-100 <= val <= 100</code></li> <li><code>0 <= left <= right < nums.length</code></li> <li>At most <code>3 * 10<sup>4</sup></code> calls will be made to <code>update</code> and <code>sumRange</code>.</li> </ul>