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            "title": "Largest Sum of Averages",
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            "content": "<p>You are given an integer array <code>nums</code> and an integer <code>k</code>. You can partition the array into <strong>at most</strong> <code>k</code> non-empty adjacent subarrays. The <strong>score</strong> of a partition is the sum of the averages of each subarray.</p>\n\n<p>Note that the partition must use every integer in <code>nums</code>, and that the score is not necessarily an integer.</p>\n\n<p>Return <em>the maximum <strong>score</strong> you can achieve of all the possible partitions</em>. Answers within <code>10<sup>-6</sup></code> of the actual answer will be accepted.</p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [9,1,2,3,9], k = 3\n<strong>Output:</strong> 20.00000\n<strong>Explanation:</strong> \nThe best choice is to partition nums into [9], [1, 2, 3], [9]. The answer is 9 + (1 + 2 + 3) / 3 + 9 = 20.\nWe could have also partitioned nums into [9, 1], [2], [3, 9], for example.\nThat partition would lead to a score of 5 + 2 + 6 = 13, which is worse.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,2,3,4,5,6,7], k = 4\n<strong>Output:</strong> 20.50000\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 100</code></li>\n\t<li><code>1 &lt;= nums[i] &lt;= 10<sup>4</sup></code></li>\n\t<li><code>1 &lt;= k &lt;= nums.length</code></li>\n</ul>\n",
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                    "code": "class Solution(object):\n    def largestSumOfAverages(self, nums, k):\n        \"\"\"\n        :type nums: List[int]\n        :type k: int\n        :rtype: float\n        \"\"\"\n        ",
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