{ "data": { "question": { "questionId": "1000085", "questionFrontendId": "LCP 16", "categoryTitle": "Algorithms", "boundTopicId": 219346, "title": "游乐园的游览计划", "titleSlug": "you-le-yuan-de-you-lan-ji-hua", "content": "", "translatedTitle": "游乐园的游览计划", "translatedContent": "

又到了一年一度的春游时间，小吴计划去游乐场游玩 1 天，游乐场总共有 N 个游乐项目，编号从 0 到 N-1。小吴给每个游乐项目定义了一个非负整数值 value[i] 表示自己的喜爱值。两个游乐项目之间会有双向路径相连，整个游乐场总共有 M 条双向路径，保存在二维数组 edges中。 小吴计划选择一个游乐项目 A 作为这一天游玩的重点项目。上午小吴准备游玩重点项目 A 以及与项目 A 相邻的两个项目 B、C （项目A、B与C要求是不同的项目，且项目B与项目C要求相邻），并返回 A ，即存在一条 A-B-C-A 的路径。 下午，小吴决定再游玩重点项目 A以及与A相邻的两个项目 B'、C'，（项目A、B'与C'要求是不同的项目，且项目B'与项目C'要求相邻），并返回 A ，即存在一条 A-B'-C'-A 的路径。下午游玩项目 B'、C' 可与上午游玩项目B、C存在重复项目。 小吴希望提前安排好游玩路径，使得喜爱值之和最大。请你返回满足游玩路径选取条件的最大喜爱值之和，如果没有这样的路径，返回 0。 注意：一天中重复游玩同一个项目并不能重复增加喜爱值了。例如：上下午游玩路径分别是 A-B-C-A与A-C-D-A 那么只能获得 value[A] + value[B] + value[C] + value[D] 的总和。

\n\n

示例 1：

\n\n
\n

输入：edges = [[0,1],[1,2],[0,2]], value = [1,2,3]

\n\n

输出：6

\n\n

解释：喜爱值之和最高的方案之一是 0->1->2->0 与 0->2->1->0 。重复游玩同一点不重复计入喜爱值，返回1+2+3=6

\n
\n\n

示例 2：

\n\n
\n

输入：edges = [[0,2],[2,1]], value = [1,2,5]

\n\n

输出：0

\n\n

解释：无满足要求的游玩路径，返回 0

\n
\n\n

示例 3：

\n\n
\n

输入：edges = [[0,1],[0,2],[0,3],[0,4],[0,5],[1,3],[2,4],[2,5],[3,4],[3,5],[4,5]], value = [7,8,6,8,9,7]

\n\n

输出：39

\n\n

解释：喜爱值之和最高的方案之一是 3->0->1->3 与 3->4->5->3 。喜爱值最高为 7+8+8+9+7=39

\n
\n\n

限制：

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