You are given a 0-indexed string word and an integer k.
At every second, you must perform the following operations:
\n\nk characters of word.k characters to the end of word.Note that you do not necessarily need to add the same characters that you removed. However, you must perform both operations at every second.
\n\nReturn the minimum time greater than zero required for word to revert to its initial state.
\n
Example 1:
\n\n\nInput: word = "abacaba", k = 3\nOutput: 2\nExplanation: At the 1st second, we remove characters "aba" from the prefix of word, and add characters "bac" to the end of word. Thus, word becomes equal to "cababac".\nAt the 2nd second, we remove characters "cab" from the prefix of word, and add "aba" to the end of word. Thus, word becomes equal to "abacaba" and reverts to its initial state.\nIt can be shown that 2 seconds is the minimum time greater than zero required for word to revert to its initial state.\n\n\n
Example 2:
\n\n\nInput: word = "abacaba", k = 4\nOutput: 1\nExplanation: At the 1st second, we remove characters "abac" from the prefix of word, and add characters "caba" to the end of word. Thus, word becomes equal to "abacaba" and reverts to its initial state.\nIt can be shown that 1 second is the minimum time greater than zero required for word to revert to its initial state.\n\n\n
Example 3:
\n\n\nInput: word = "abcbabcd", k = 2\nOutput: 4\nExplanation: At every second, we will remove the first 2 characters of word, and add the same characters to the end of word.\nAfter 4 seconds, word becomes equal to "abcbabcd" and reverts to its initial state.\nIt can be shown that 4 seconds is the minimum time greater than zero required for word to revert to its initial state.\n\n\n
\n
Constraints:
\n\n1 <= word.length <= 1061 <= k <= word.lengthword consists only of lowercase English letters.给你一个下标从 0 开始的字符串 word 和一个整数 k 。
在每一秒，你必须执行以下操作：
\n\nword 的前 k 个字符。word 的末尾添加 k 个任意字符。注意 添加的字符不必和移除的字符相同。但是，必须在每一秒钟都执行 两种 操作。
\n\n返回将 word 恢复到其 初始 状态所需的 最短 时间（该时间必须大于零）。
\n\n
示例 1：
\n\n\n输入：word = \"abacaba\", k = 3\n输出：2\n解释：\n第 1 秒，移除 word 的前缀 \"aba\"，并在末尾添加 \"bac\" 。因此，word 变为 \"cababac\"。\n第 2 秒，移除 word 的前缀 \"cab\"，并在末尾添加 \"aba\" 。因此，word 变为 \"abacaba\" 并恢复到始状态。\n可以证明，2 秒是 word 恢复到其初始状态所需的最短时间。\n\n\n
示例 2：
\n\n\n输入：word = \"abacaba\", k = 4\n输出：1\n解释：\n第 1 秒，移除 word 的前缀 \"abac\"，并在末尾添加 \"caba\" 。因此，word 变为 \"abacaba\" 并恢复到初始状态。\n可以证明，1 秒是 word 恢复到其初始状态所需的最短时间。\n\n\n
示例 3：
\n\n\n输入：word = \"abcbabcd\", k = 2\n输出：4\n解释：\n每一秒，我们都移除 word 的前 2 个字符，并在 word 末尾添加相同的字符。\n4 秒后，word 变为 \"abcbabcd\" 并恢复到初始状态。\n可以证明，4 秒是 word 恢复到其初始状态所需的最短时间。\n\n\n
\n\n
提示：
\n\n1 <= word.length <= 1061 <= k <= word.lengthword仅由小写英文字母组成。K in O(N).",
"Use Z-function."
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