You and a gang of thieves are planning on robbing a bank. You are given a 0-indexed integer array security, where security[i] is the number of guards on duty on the ith day. The days are numbered starting from 0. You are also given an integer time.
The ith day is a good day to rob the bank if:
time days before and after the ith day,time days before i are non-increasing, andtime days after i are non-decreasing.More formally, this means day i is a good day to rob the bank if and only if security[i - time] >= security[i - time + 1] >= ... >= security[i] <= ... <= security[i + time - 1] <= security[i + time].
Return a list of all days (0-indexed) that are good days to rob the bank. The order that the days are returned in does not matter.
\n\n\n
Example 1:
\n\n\nInput: security = [5,3,3,3,5,6,2], time = 2\nOutput: [2,3]\nExplanation:\nOn day 2, we have security[0] >= security[1] >= security[2] <= security[3] <= security[4].\nOn day 3, we have security[1] >= security[2] >= security[3] <= security[4] <= security[5].\nNo other days satisfy this condition, so days 2 and 3 are the only good days to rob the bank.\n\n\n
Example 2:
\n\n\nInput: security = [1,1,1,1,1], time = 0\nOutput: [0,1,2,3,4]\nExplanation:\nSince time equals 0, every day is a good day to rob the bank, so return every day.\n\n\n
Example 3:
\n\n\nInput: security = [1,2,3,4,5,6], time = 2\nOutput: []\nExplanation:\nNo day has 2 days before it that have a non-increasing number of guards.\nThus, no day is a good day to rob the bank, so return an empty list.\n\n\n
\n
Constraints:
\n\n1 <= security.length <= 1050 <= security[i], time <= 105你和朋友们准备去野炊。给你一个下标从 0 开始的整数数组 security ，其中 security[i] 是第 i 天的建议出行指数。日子从 0 开始编号。同时给你一个整数 time 。
如果第 i 天满足以下所有条件，我们称它为一个适合野炊的日子：
i 天前和后都分别至少有 time 天。i 天前连续 time 天建议出行指数都是非递增的。i 天后连续 time 天建议出行指数都是非递减的。更正式的，第 i 天是一个适合野炊的日子当且仅当：security[i - time] >= security[i - time + 1] >= ... >= security[i] <= ... <= security[i + time - 1] <= security[i + time].
请你返回一个数组，包含 所有 适合野炊的日子（下标从 0 开始）。返回的日子可以 任意 顺序排列。
\n\n\n\n
示例 1：
\n\n\n输入：security = [5,3,3,3,5,6,2], time = 2\n输出：[2,3]\n解释：\n第 2 天，我们有 security[0] >= security[1] >= security[2] <= security[3] <= security[4] 。\n第 3 天，我们有 security[1] >= security[2] >= security[3] <= security[4] <= security[5] 。\n没有其他日子符合这个条件，所以日子 2 和 3 是适合野炊的日子。\n\n\n
示例 2：
\n\n\n输入：security = [1,1,1,1,1], time = 0\n输出：[0,1,2,3,4]\n解释：\n因为 time 等于 0 ，所以每一天都是适合野炊的日子，所以返回每一天。\n\n\n
示例 3：
\n\n\n输入：security = [1,2,3,4,5,6], time = 2\n输出：[]\n解释：\n没有任何一天的前 2 天建议出行指数是非递增的。\n所以没有适合野炊的日子，返回空数组。\n\n\n
\n\n
提示：
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