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            "questionId": "1647",
            "questionFrontendId": "1540",
            "categoryTitle": "Algorithms",
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            "title": "Can Convert String in K Moves",
            "titleSlug": "can-convert-string-in-k-moves",
            "content": "<p>Given two strings&nbsp;<code>s</code>&nbsp;and&nbsp;<code>t</code>, your goal is to convert&nbsp;<code>s</code>&nbsp;into&nbsp;<code>t</code>&nbsp;in&nbsp;<code>k</code><strong>&nbsp;</strong>moves or less.</p>\n\n<p>During the&nbsp;<code>i<sup>th</sup></code>&nbsp;(<font face=\"monospace\"><code>1 &lt;= i &lt;= k</code>)&nbsp;</font>move you can:</p>\n\n<ul>\n\t<li>Choose any index&nbsp;<code>j</code>&nbsp;(1-indexed) from&nbsp;<code>s</code>, such that&nbsp;<code>1 &lt;= j &lt;= s.length</code>&nbsp;and <code>j</code>&nbsp;has not been chosen in any previous move,&nbsp;and shift the character at that index&nbsp;<code>i</code>&nbsp;times.</li>\n\t<li>Do nothing.</li>\n</ul>\n\n<p>Shifting a character means replacing it by the next letter in the alphabet&nbsp;(wrapping around so that&nbsp;<code>&#39;z&#39;</code>&nbsp;becomes&nbsp;<code>&#39;a&#39;</code>). Shifting a character by&nbsp;<code>i</code>&nbsp;means applying the shift operations&nbsp;<code>i</code>&nbsp;times.</p>\n\n<p>Remember that any index&nbsp;<code>j</code>&nbsp;can be picked at most once.</p>\n\n<p>Return&nbsp;<code>true</code>&nbsp;if it&#39;s possible to convert&nbsp;<code>s</code>&nbsp;into&nbsp;<code>t</code>&nbsp;in no more than&nbsp;<code>k</code>&nbsp;moves, otherwise return&nbsp;<code>false</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;input&quot;, t = &quot;ouput&quot;, k = 9\n<strong>Output:</strong> true\n<b>Explanation: </b>In the 6th move, we shift &#39;i&#39; 6 times to get &#39;o&#39;. And in the 7th move we shift &#39;n&#39; to get &#39;u&#39;.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;abc&quot;, t = &quot;bcd&quot;, k = 10\n<strong>Output:</strong> false\n<strong>Explanation: </strong>We need to shift each character in s one time to convert it into t. We can shift &#39;a&#39; to &#39;b&#39; during the 1st move. However, there is no way to shift the other characters in the remaining moves to obtain t from s.\n</pre>\n\n<p><strong>Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;aab&quot;, t = &quot;bbb&quot;, k = 27\n<strong>Output:</strong> true\n<b>Explanation: </b>In the 1st move, we shift the first &#39;a&#39; 1 time to get &#39;b&#39;. In the 27th move, we shift the second &#39;a&#39; 27 times to get &#39;b&#39;.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= s.length, t.length &lt;= 10^5</code></li>\n\t<li><code>0 &lt;= k &lt;= 10^9</code></li>\n\t<li><code>s</code>, <code>t</code> contain&nbsp;only lowercase English letters.</li>\n</ul>\n",
            "translatedTitle": "K 次操作转变字符串",
            "translatedContent": "<p>给你两个字符串&nbsp;<code>s</code>&nbsp;和&nbsp;<code>t</code>&nbsp;,你的目标是在 <code>k</code>&nbsp;次操作以内把字符串&nbsp;<code>s</code>&nbsp;转变成&nbsp;<code>t</code>&nbsp;。</p>\n\n<p>在第 <code>i</code>&nbsp;次操作时(<code>1 &lt;= i &lt;= k</code>),你可以选择进行如下操作:</p>\n\n<ul>\n\t<li>选择字符串 <code>s</code>&nbsp;中满足 <code>1 &lt;= j &lt;= s.length</code>&nbsp;且之前未被选过的任意下标 <code>j</code>&nbsp;(下标从 1 开始),并将此位置的字符切换 <code>i</code>&nbsp;次。</li>\n\t<li>不进行任何操作。</li>\n</ul>\n\n<p>切换 1 个字符的意思是用字母表中该字母的下一个字母替换它(字母表环状接起来,所以 <code>'z'</code>&nbsp;切换后会变成 <code>'a'</code>)。第 <code>i</code>&nbsp;次操作意味着该字符应切换&nbsp;<code>i</code>&nbsp;次</p>\n\n<p>请记住任意一个下标 <code>j</code>&nbsp;最多只能被操作&nbsp;1 次。</p>\n\n<p>如果在不超过 <code>k</code>&nbsp;次操作内可以把字符串 <code>s</code>&nbsp;转变成 <code>t</code>&nbsp;,那么请你返回&nbsp;<code>true</code>&nbsp;,否则请你返回&nbsp;<code>false</code>&nbsp;。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1:</strong></p>\n\n<pre>\n<strong>输入:</strong>s = \"input\", t = \"ouput\", k = 9\n<strong>输出:</strong>true\n<strong>解释:</strong>第 6 次操作时,我们将 'i' 切换 6 次得到 'o' 。第 7 次操作时,我们将 'n' 切换 7 次得到 'u' 。\n</pre>\n\n<p><strong>示例 2:</strong></p>\n\n<pre>\n<strong>输入:</strong>s = \"abc\", t = \"bcd\", k = 10\n<strong>输出:</strong>false\n<strong>解释:</strong>我们需要将每个字符切换 1 次才能得到 t 。我们可以在第 1 次操作时将 'a' 切换成 'b' ,但另外 2 个字母在剩余操作中无法再转变为 t 中对应字母。\n</pre>\n\n<p><strong>示例 3:</strong></p>\n\n<pre>\n<strong>输入:</strong>s = \"aab\", t = \"bbb\", k = 27\n<strong>输出:</strong>true\n<strong>解释:</strong>第 1 次操作时,我们将第一个 'a' 切换 1 次得到 'b' 。在第 27 次操作时,我们将第二个字母 'a' 切换 27 次得到 'b' 。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= s.length, t.length &lt;= 10^5</code></li>\n\t<li><code>0 &lt;= k &lt;= 10^9</code></li>\n\t<li><code>s</code>&nbsp;和&nbsp;<code>t</code>&nbsp;只包含小写英文字母。</li>\n</ul>\n",
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