{ "data": { "question": { "questionId": "1948", "questionFrontendId": "1795", "boundTopicId": null, "title": "Rearrange Products Table", "titleSlug": "rearrange-products-table", "content": "

Table: Products

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\n+-------------+---------+\n| Column Name | Type    |\n+-------------+---------+\n| product_id  | int     |\n| store1      | int     |\n| store2      | int     |\n| store3      | int     |\n+-------------+---------+\nproduct_id is the primary key for this table.\nEach row in this table indicates the product's price in 3 different stores: store1, store2, and store3.\nIf the product is not available in a store, the price will be null in that store's column.\n
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Write an SQL query to rearrange the Products table so that each row has (product_id, store, price). If a product is not available in a store, do not include a row with that product_id and store combination in the result table.

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Return the result table in any order.

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The query result format is in the following example.

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Example 1:

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\nInput: \nProducts table:\n+------------+--------+--------+--------+\n| product_id | store1 | store2 | store3 |\n+------------+--------+--------+--------+\n| 0          | 95     | 100    | 105    |\n| 1          | 70     | null   | 80     |\n+------------+--------+--------+--------+\nOutput: \n+------------+--------+-------+\n| product_id | store  | price |\n+------------+--------+-------+\n| 0          | store1 | 95    |\n| 0          | store2 | 100   |\n| 0          | store3 | 105   |\n| 1          | store1 | 70    |\n| 1          | store3 | 80    |\n+------------+--------+-------+\nExplanation: \nProduct 0 is available in all three stores with prices 95, 100, and 105 respectively.\nProduct 1 is available in store1 with price 70 and store3 with price 80. The product is not available in store2.\n
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MySQL 8.0.

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mssql server 2019.

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Oracle Sql 11.2.

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