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"title": "Count Common Words With One Occurrence",
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"content": "<p>Given two string arrays <code>words1</code> and <code>words2</code>, return <em>the number of strings that appear <strong>exactly once</strong> in <b>each</b> of the two arrays.</em></p>\n\n<p> </p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> words1 = ["leetcode","is","amazing","as","is"], words2 = ["amazing","leetcode","is"]\n<strong>Output:</strong> 2\n<strong>Explanation:</strong>\n- "leetcode" appears exactly once in each of the two arrays. We count this string.\n- "amazing" appears exactly once in each of the two arrays. We count this string.\n- "is" appears in each of the two arrays, but there are 2 occurrences of it in words1. We do not count this string.\n- "as" appears once in words1, but does not appear in words2. We do not count this string.\nThus, there are 2 strings that appear exactly once in each of the two arrays.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> words1 = ["b","bb","bbb"], words2 = ["a","aa","aaa"]\n<strong>Output:</strong> 0\n<strong>Explanation:</strong> There are no strings that appear in each of the two arrays.\n</pre>\n\n<p><strong>Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> words1 = ["a","ab"], words2 = ["a","a","a","ab"]\n<strong>Output:</strong> 1\n<strong>Explanation:</strong> The only string that appears exactly once in each of the two arrays is "ab".\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 <= words1.length, words2.length <= 1000</code></li>\n\t<li><code>1 <= words1[i].length, words2[j].length <= 30</code></li>\n\t<li><code>words1[i]</code> and <code>words2[j]</code> consists only of lowercase English letters.</li>\n</ul>\n",
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"code": "class Solution {\npublic:\n int countWords(vector<string>& words1, vector<string>& words2) {\n \n }\n};",
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"code": "class Solution {\n public int countWords(String[] words1, String[] words2) {\n \n }\n}",
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"code": "class Solution(object):\n def countWords(self, words1, words2):\n \"\"\"\n :type words1: List[str]\n :type words2: List[str]\n :rtype: int\n \"\"\"\n ",
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"code": "class Solution:\n def countWords(self, words1: List[str], words2: List[str]) -> int:\n ",
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"code": "\n\nint countWords(char ** words1, int words1Size, char ** words2, int words2Size){\n\n}",
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"code": "/**\n * @param {string[]} words1\n * @param {string[]} words2\n * @return {number}\n */\nvar countWords = function(words1, words2) {\n \n};",
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"code": "# @param {String[]} words1\n# @param {String[]} words2\n# @return {Integer}\ndef count_words(words1, words2)\n \nend",
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"code": "impl Solution {\n pub fn count_words(words1: Vec<String>, words2: Vec<String>) -> i32 {\n \n }\n}",
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"code": "class Solution {\n\n /**\n * @param String[] $words1\n * @param String[] $words2\n * @return Integer\n */\n function countWords($words1, $words2) {\n \n }\n}",
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"code": "(define/contract (count-words words1 words2)\n (-> (listof string?) (listof string?) exact-integer?)\n\n )",
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"code": "defmodule Solution do\n @spec count_words(words1 :: [String.t], words2 :: [String.t]) :: integer\n def count_words(words1, words2) do\n\n end\nend",
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"hints": [
"Could you try every word?",
"Could you use a hash map to achieve a good complexity?"
],
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"sampleTestCase": "[\"leetcode\",\"is\",\"amazing\",\"as\",\"is\"]\n[\"amazing\",\"leetcode\",\"is\"]",
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