<p>We have two arrays <code>arr1</code> and <code>arr2</code> which are initially empty. You need to add positive integers to them such that they satisfy all the following conditions:</p> <ul> <li><code>arr1</code> contains <code>uniqueCnt1</code> <strong>distinct</strong> positive integers, each of which is <strong>not divisible</strong> by <code>divisor1</code>.</li> <li><code>arr2</code> contains <code>uniqueCnt2</code> <strong>distinct</strong> positive integers, each of which is <strong>not divisible</strong> by <code>divisor2</code>.</li> <li><strong>No</strong> integer is present in both <code>arr1</code> and <code>arr2</code>.</li> </ul> <p>Given <code>divisor1</code>, <code>divisor2</code>, <code>uniqueCnt1</code>, and <code>uniqueCnt2</code>, return <em>the <strong>minimum possible maximum</strong> integer that can be present in either array</em>.</p> <p> </p> <p><strong class="example">Example 1:</strong></p> <pre> <strong>Input:</strong> divisor1 = 2, divisor2 = 7, uniqueCnt1 = 1, uniqueCnt2 = 3 <strong>Output:</strong> 4 <strong>Explanation:</strong> We can distribute the first 4 natural numbers into arr1 and arr2. arr1 = [1] and arr2 = [2,3,4]. We can see that both arrays satisfy all the conditions. Since the maximum value is 4, we return it. </pre> <p><strong class="example">Example 2:</strong></p> <pre> <strong>Input:</strong> divisor1 = 3, divisor2 = 5, uniqueCnt1 = 2, uniqueCnt2 = 1 <strong>Output:</strong> 3 <strong>Explanation:</strong> Here arr1 = [1,2], and arr2 = [3] satisfy all conditions. Since the maximum value is 3, we return it.</pre> <p><strong class="example">Example 3:</strong></p> <pre> <strong>Input:</strong> divisor1 = 2, divisor2 = 4, uniqueCnt1 = 8, uniqueCnt2 = 2 <strong>Output:</strong> 15 <strong>Explanation:</strong> Here, the final possible arrays can be arr1 = [1,3,5,7,9,11,13,15], and arr2 = [2,6]. It can be shown that it is not possible to obtain a lower maximum satisfying all conditions. </pre> <p> </p> <p><strong>Constraints:</strong></p> <ul> <li><code>2 <= divisor1, divisor2 <= 10<sup>5</sup></code></li> <li><code>1 <= uniqueCnt1, uniqueCnt2 < 10<sup>9</sup></code></li> <li><code>2 <= uniqueCnt1 + uniqueCnt2 <= 10<sup>9</sup></code></li> </ul>