{ "data": { "question": { "questionId": "2849", "questionFrontendId": "2763", "categoryTitle": "Algorithms", "boundTopicId": 2325356, "title": "Sum of Imbalance Numbers of All Subarrays", "titleSlug": "sum-of-imbalance-numbers-of-all-subarrays", "content": "

The imbalance number of a 0-indexed integer array arr of length n is defined as the number of indices in sarr = sorted(arr) such that:

\n\n\n\n

Here, sorted(arr) is the function that returns the sorted version of arr.

\n\n

Given a 0-indexed integer array nums, return the sum of imbalance numbers of all its subarrays.

\n\n

A subarray is a contiguous non-empty sequence of elements within an array.

\n\n

 

\n

Example 1:

\n\n
\nInput: nums = [2,3,1,4]\nOutput: 3\nExplanation: There are 3 subarrays with non-zero imbalance numbers:\n- Subarray [3, 1] with an imbalance number of 1.\n- Subarray [3, 1, 4] with an imbalance number of 1.\n- Subarray [1, 4] with an imbalance number of 1.\nThe imbalance number of all other subarrays is 0. Hence, the sum of imbalance numbers of all the subarrays of nums is 3. \n
\n\n

Example 2:

\n\n
\nInput: nums = [1,3,3,3,5]\nOutput: 8\nExplanation: There are 7 subarrays with non-zero imbalance numbers:\n- Subarray [1, 3] with an imbalance number of 1.\n- Subarray [1, 3, 3] with an imbalance number of 1.\n- Subarray [1, 3, 3, 3] with an imbalance number of 1.\n- Subarray [1, 3, 3, 3, 5] with an imbalance number of 2. \n- Subarray [3, 3, 3, 5] with an imbalance number of 1. \n- Subarray [3, 3, 5] with an imbalance number of 1.\n- Subarray [3, 5] with an imbalance number of 1.\nThe imbalance number of all other subarrays is 0. Hence, the sum of imbalance numbers of all the subarrays of nums is 8. 
\n\n

 

\n

Constraints:

\n\n\n", "translatedTitle": "所有子数组中不平衡数字之和", "translatedContent": "

一个长度为 n 下标从 0 开始的整数数组 arr 的 不平衡数字 定义为,在 sarr = sorted(arr) 数组中,满足以下条件的下标数目:

\n\n\n\n

这里,sorted(arr) 表示将数组 arr 排序后得到的数组。

\n\n

给你一个下标从 0 开始的整数数组 nums ,请你返回它所有 子数组 的 不平衡数字 之和。

\n\n

子数组指的是一个数组中连续一段 非空 的元素序列。

\n\n

 

\n\n

示例 1:

\n\n
输入:nums = [2,3,1,4]\n输出:3\n解释:总共有 3 个子数组有非 0 不平衡数字:\n- 子数组 [3, 1] ,不平衡数字为 1 。\n- 子数组 [3, 1, 4] ,不平衡数字为 1 。\n- 子数组 [1, 4] ,不平衡数字为 1 。\n其他所有子数组的不平衡数字都是 0 ,所以所有子数组的不平衡数字之和为 3 。\n
\n\n

示例 2:

\n\n
输入:nums = [1,3,3,3,5]\n输出:8\n解释:总共有 7 个子数组有非 0 不平衡数字:\n- 子数组 [1, 3] ,不平衡数字为 1 。\n- 子数组 [1, 3, 3] ,不平衡数字为 1 。\n- 子数组 [1, 3, 3, 3] ,不平衡数字为 1 。\n- 子数组 [1, 3, 3, 3, 5] ,不平衡数字为 2 。\n- 子数组 [3, 3, 3, 5] ,不平衡数字为 1 。\n- 子数组 [3, 3, 5] ,不平衡数字为 1 。\n- 子数组 [3, 5] ,不平衡数字为 1 。\n其他所有子数组的不平衡数字都是 0 ,所以所有子数组的不平衡数字之和为 8 。
\n\n

 

\n\n

提示:

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