{ "data": { "question": { "questionId": "900", "questionFrontendId": "869", "categoryTitle": "Algorithms", "boundTopicId": 1053, "title": "Reordered Power of 2", "titleSlug": "reordered-power-of-2", "content": "
You are given an integer n
. We reorder the digits in any order (including the original order) such that the leading digit is not zero.
Return true
if and only if we can do this so that the resulting number is a power of two.
\n
Example 1:
\n\n\nInput: n = 1\nOutput: true\n\n\n
Example 2:
\n\n\nInput: n = 10\nOutput: false\n\n\n
\n
Constraints:
\n\n1 <= n <= 109
给定正整数 n
,我们按任何顺序(包括原始顺序)将数字重新排序,注意其前导数字不能为零。
如果我们可以通过上述方式得到 2 的幂,返回 true
;否则,返回 false
。
\n\n
示例 1:
\n\n\n输入:n = 1\n输出:true\n\n\n
示例 2:
\n\n\n输入:n = 10\n输出:false\n\n\n
\n\n
提示:
\n\n1 <= n <= 109
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