You are given an integer array nums and a non-negative integer k. In one operation, you can increase or decrease any element by 1.
Return the minimum number of operations needed to make the median of nums equal to k.
\n
Example 1:
\n\nInput: nums = [2,5,6,8,5], k = 4
\n\nOutput: 2
\n\nExplanation:
\n\nWe can subtract one from nums[1] and nums[4] to obtain [2, 4, 6, 8, 4]. The median of the resulting array is equal to k.
Example 2:
\n\nInput: nums = [2,5,6,8,5], k = 7
\n\nOutput: 3
\n\nExplanation:
\n\nWe can add one to nums[1] twice and add one to nums[2] once to obtain [2, 7, 7, 8, 5].
Example 3:
\n\nInput: nums = [1,2,3,4,5,6], k = 4
\n\nOutput: 0
\n\nExplanation:
\n\nThe median of the array is already equal to k.
\n
Constraints:
\n\n1 <= nums.length <= 2 * 1051 <= nums[i] <= 1091 <= k <= 109给你一个整数数组 nums 和一个 非负 整数 k 。
一次操作中，你可以选择任一下标 i ，然后将 nums[i] 加 1 或者减 1 。
请你返回将 nums 中位数 变为 k 所需要的 最少 操作次数。
一个数组的 中位数 指的是数组按 非递减 顺序排序后最中间的元素。如果数组长度为偶数，我们选择中间两个数的较大值为中位数。
\n\n\n\n
示例 1：
\n\n输入：nums = [2,5,6,8,5], k = 4
\n\n输出：2
\n\n解释：我们将 nums[1] 和 nums[4] 减 1 得到 [2, 4, 6, 8, 4] 。现在数组的中位数等于 k 。所以答案为 2 。
示例 2：
\n\n输入：nums = [2,5,6,8,5], k = 7
\n\n输出：3
\n\n解释：我们将 nums[1] 增加 1 两次，并且将 nums[2] 增加 1 一次，得到 [2, 7, 7, 8, 5] 。结果数组的中位数等于 k 。所以答案为 3 。
示例 3：
\n\n输入：nums = [1,2,3,4,5,6], k = 4
\n\n输出：0
\n\n解释：数组中位数已经等于 k 了，所以不需要进行任何操作。
\n\n
提示：
\n\n1 <= nums.length <= 2 * 1051 <= nums[i] <= 1091 <= k <= 109nums in non-descending order.",
"For all the smaller values on the left side of the median, change them to k if they are larger than k.",
"For all the larger values on the right side of the median, change them to k if they are smaller than k."
],
"solution": null,
"status": null,
"sampleTestCase": "[2,5,6,8,5]\n4",
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