You are given an array tasks where tasks[i] = [actuali, minimumi]:
actuali is the actual amount of energy you spend to finish the ith task.minimumi is the minimum amount of energy you require to begin the ith task.For example, if the task is [10, 12] and your current energy is 11, you cannot start this task. However, if your current energy is 13, you can complete this task, and your energy will be 3 after finishing it.
You can finish the tasks in any order you like.
\n\nReturn the minimum initial amount of energy you will need to finish all the tasks.
\n\n\n
Example 1:
\n\n\nInput: tasks = [[1,2],[2,4],[4,8]]\nOutput: 8\nExplanation:\nStarting with 8 energy, we finish the tasks in the following order:\n - 3rd task. Now energy = 8 - 4 = 4.\n - 2nd task. Now energy = 4 - 2 = 2.\n - 1st task. Now energy = 2 - 1 = 1.\nNotice that even though we have leftover energy, starting with 7 energy does not work because we cannot do the 3rd task.\n\n
Example 2:
\n\n\nInput: tasks = [[1,3],[2,4],[10,11],[10,12],[8,9]]\nOutput: 32\nExplanation:\nStarting with 32 energy, we finish the tasks in the following order:\n - 1st task. Now energy = 32 - 1 = 31.\n - 2nd task. Now energy = 31 - 2 = 29.\n - 3rd task. Now energy = 29 - 10 = 19.\n - 4th task. Now energy = 19 - 10 = 9.\n - 5th task. Now energy = 9 - 8 = 1.\n\n
Example 3:
\n\n\nInput: tasks = [[1,7],[2,8],[3,9],[4,10],[5,11],[6,12]]\nOutput: 27\nExplanation:\nStarting with 27 energy, we finish the tasks in the following order:\n - 5th task. Now energy = 27 - 5 = 22.\n - 2nd task. Now energy = 22 - 2 = 20.\n - 3rd task. Now energy = 20 - 3 = 17.\n - 1st task. Now energy = 17 - 1 = 16.\n - 4th task. Now energy = 16 - 4 = 12.\n - 6th task. Now energy = 12 - 6 = 6.\n\n\n
\n
Constraints:
\n\n1 <= tasks.length <= 1051 <= actuali <= minimumi <= 104给你一个任务数组 tasks ，其中 tasks[i] = [actuali, minimumi] ：
actuali 是完成第 i 个任务 需要耗费 的实际能量。minimumi 是开始第 i 个任务前需要达到的最低能量。比方说，如果任务为 [10, 12] 且你当前的能量为 11 ，那么你不能开始这个任务。如果你当前的能量为 13 ，你可以完成这个任务，且完成它后剩余能量为 3 。
你可以按照 任意顺序 完成任务。
\n\n请你返回完成所有任务的 最少 初始能量。
\n\n\n\n
示例 1：
\n\n输入：tasks = [[1,2],[2,4],[4,8]]\n输出：8\n解释：\n一开始有 8 能量，我们按照如下顺序完成任务：\n - 完成第 3 个任务，剩余能量为 8 - 4 = 4 。\n - 完成第 2 个任务，剩余能量为 4 - 2 = 2 。\n - 完成第 1 个任务，剩余能量为 2 - 1 = 1 。\n注意到尽管我们有能量剩余，但是如果一开始只有 7 能量是不能完成所有任务的，因为我们无法开始第 3 个任务。\n\n
示例 2：
\n\n输入：tasks = [[1,3],[2,4],[10,11],[10,12],[8,9]]\n输出：32\n解释：\n一开始有 32 能量，我们按照如下顺序完成任务：\n - 完成第 1 个任务，剩余能量为 32 - 1 = 31 。\n - 完成第 2 个任务，剩余能量为 31 - 2 = 29 。\n - 完成第 3 个任务，剩余能量为 29 - 10 = 19 。\n - 完成第 4 个任务，剩余能量为 19 - 10 = 9 。\n - 完成第 5 个任务，剩余能量为 9 - 8 = 1 。\n\n
示例 3：
\n\n输入：tasks = [[1,7],[2,8],[3,9],[4,10],[5,11],[6,12]]\n输出：27\n解释：\n一开始有 27 能量，我们按照如下顺序完成任务：\n - 完成第 5 个任务，剩余能量为 27 - 5 = 22 。\n - 完成第 2 个任务，剩余能量为 22 - 2 = 20 。\n - 完成第 3 个任务，剩余能量为 20 - 3 = 17 。\n - 完成第 1 个任务，剩余能量为 17 - 1 = 16 。\n - 完成第 4 个任务，剩余能量为 16 - 4 = 12 。\n - 完成第 6 个任务，剩余能量为 12 - 6 = 6 。\n\n\n
\n\n
提示：
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collections<\\/a>\\u3002\\u5982\\u679c\\u60a8\\u9700\\u8981\\u4f7f\\u7528\\u5176\\u4ed6\\u5e93\\u51fd\\u6570\\uff0c\\u8bf7\\u81ea\\u884c\\u5bfc\\u5165\\u3002<\\/p>\\r\\n\\r\\n \\u6ce8\\u610f Python 2.7 \\u5c06\\u57282020\\u5e74\\u540e\\u4e0d\\u518d\\u7ef4\\u62a4<\\/a>\\u3002 \\u5982\\u60f3\\u4f7f\\u7528\\u6700\\u65b0\\u7248\\u7684Python\\uff0c\\u8bf7\\u9009\\u62e9Python 3\\u3002<\\/p>\"],\"c\":[\"C\",\" \\u7248\\u672c\\uff1a \\u7f16\\u8bd1\\u65f6\\uff0c\\u5c06\\u4f1a\\u91c7\\u7528 \\u4e3a\\u4e86\\u4f7f\\u7528\\u65b9\\u4fbf\\uff0c\\u5927\\u90e8\\u5206\\u6807\\u51c6\\u5e93\\u7684\\u5934\\u6587\\u4ef6\\u5df2\\u7ecf\\u88ab\\u81ea\\u52a8\\u5bfc\\u5165\\u3002<\\/p>\\r\\n\\r\\n \\u5982\\u60f3\\u4f7f\\u7528\\u54c8\\u5e0c\\u8868\\u8fd0\\u7b97, \\u60a8\\u53ef\\u4ee5\\u4f7f\\u7528 uthash<\\/a>\\u3002 \\\"uthash.h\\\"\\u5df2\\u7ecf\\u9ed8\\u8ba4\\u88ab\\u5bfc\\u5165\\u3002\\u8bf7\\u770b\\u5982\\u4e0b\\u793a\\u4f8b:<\\/p>\\r\\n\\r\\n 1. 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