You are given a 0-indexed array nums comprising of n non-negative integers.
In one operation, you must:
\n\ni such that 1 <= i < n and nums[i] > 0.nums[i] by 1.nums[i - 1] by 1.Return the minimum possible value of the maximum integer of nums after performing any number of operations.
\n
Example 1:
\n\n\nInput: nums = [3,7,1,6]\nOutput: 5\nExplanation:\nOne set of optimal operations is as follows:\n1. Choose i = 1, and nums becomes [4,6,1,6].\n2. Choose i = 3, and nums becomes [4,6,2,5].\n3. Choose i = 1, and nums becomes [5,5,2,5].\nThe maximum integer of nums is 5. It can be shown that the maximum number cannot be less than 5.\nTherefore, we return 5.\n\n\n
Example 2:
\n\n\nInput: nums = [10,1]\nOutput: 10\nExplanation:\nIt is optimal to leave nums as is, and since 10 is the maximum value, we return 10.\n\n\n
\n
Constraints:
\n\nn == nums.length2 <= n <= 1050 <= nums[i] <= 109给你一个下标从 0 开始的数组 nums ，它含有 n 个非负整数。
每一步操作中，你需要：
\n\n1 <= i < n 的整数 i ，且 nums[i] > 0 。nums[i] 减 1 。nums[i - 1] 加 1 。你可以对数组执行 任意 次上述操作，请你返回可以得到的 nums 数组中 最大值 最小 为多少。
\n\n
示例 1：
\n\n输入：nums = [3,7,1,6]\n输出：5\n解释：\n一串最优操作是：\n1. 选择 i = 1 ，nums 变为 [4,6,1,6] 。\n2. 选择 i = 3 ，nums 变为 [4,6,2,5] 。\n3. 选择 i = 1 ，nums 变为 [5,5,2,5] 。\nnums 中最大值为 5 。无法得到比 5 更小的最大值。\n所以我们返回 5 。\n\n\n
示例 2：
\n\n输入：nums = [10,1]\n输出：10\n解释：\n最优解是不改动 nums ，10 是最大值，所以返回 10 。\n\n\n
\n\n
提示：
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