{ "data": { "question": { "questionId": "100326", "questionFrontendId": "LCR 171", "categoryTitle": "Algorithms", "boundTopicId": 87896, "title": "训练计划 V", "titleSlug": "liang-ge-lian-biao-de-di-yi-ge-gong-gong-jie-dian-lcof", "content": "English description is not available for the problem. Please switch to Chinese.", "translatedTitle": "训练计划 V", "translatedContent": "

某教练同时带教两位学员，分别以链表 l1、l2 记录了两套核心肌群训练计划，节点值为训练项目编号。两套计划仅有前半部分热身项目不同，后续正式训练项目相同。请设计一个程序找出并返回第一个正式训练项目编号。如果两个链表不存在相交节点，返回 null 。

\n\n

如下面的两个链表：

\n\n

\"\"

\n\n

在节点 c1 开始相交。

\n\n

输入说明：

\n\n

intersectVal - 相交的起始节点的值。如果不存在相交节点，这一值为 0

\n\n

l1 - 第一个训练计划链表

\n\n

l2 - 第二个训练计划链表

\n\n

skip1 - 在 l1 中（从头节点开始）跳到交叉节点的节点数

\n\n

skip2 - 在 l2 中（从头节点开始）跳到交叉节点的节点数

\n\n

程序将根据这些输入创建链式数据结构，并将两个头节点 head1 和 head2 传递给你的程序。如果程序能够正确返回相交节点，那么你的解决方案将被视作正确答案 。

\n\n

 

\n\n

示例 1：

\n\n

\"\"

\n\n
\n输入：intersectVal = 8, listA = [4,1,8,4,5], listB = [5,0,1,8,4,5], skipA = 2, skipB = 3\n输出：Reference of the node with value = 8\n解释：第一个正式训练项目编号为 8 （注意，如果两个列表相交则不能为 0）。从各自的表头开始算起，链表 A 为 [4,1,8,4,5]，链表 B 为 [5,0,1,8,4,5]。在 A 中，相交节点前有 2 个节点；在 B 中，相交节点前有 3 个节点。\n
\n\n

 

\n\n

示例 2：

\n\n

\"\"

\n\n
\n输入：intersectVal = 2, listA = [0,9,1,2,4], listB = [3,2,4], skipA = 3, skipB = 1\n输出：Reference of the node with value = 2\n解释：第一个正式训练项目编号为 2 （注意，如果两个列表相交则不能为 0）。从各自的表头开始算起，链表 A 为 [0,9,1,2,4]，链表 B 为 [3,2,4]。在 A 中，相交节点前有 3 个节点；在 B 中，相交节点前有 1 个节点。\n
\n\n

 

\n\n

示例 3：

\n\n

\"\"

\n\n
\n输入：intersectVal = 0, listA = [2,6,4], listB = [1,5], skipA = 3, skipB = 2\n输出：null\n解释：两套计划完全不同，返回 null。从各自的表头开始算起，链表 A 为 [2,6,4]，链表 B 为 [1,5]。由于这两个链表不相交，所以 intersectVal 必须为 0，而 skipA 和 skipB 可以是任意值。\n
\n\n

 

\n\n

注意：

\n\n\n\n

 

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