{ "data": { "question": { "questionId": "3220", "questionFrontendId": "2960", "categoryTitle": "Algorithms", "boundTopicId": 2559225, "title": "Count Tested Devices After Test Operations", "titleSlug": "count-tested-devices-after-test-operations", "content": "

You are given a 0-indexed integer array batteryPercentages having length n, denoting the battery percentages of n 0-indexed devices.

\n\n

Your task is to test each device i in order from 0 to n - 1, by performing the following test operations:

\n\n\n\n

Return an integer denoting the number of devices that will be tested after performing the test operations in order.

\n\n

 

\n

Example 1:

\n\n
\nInput: batteryPercentages = [1,1,2,1,3]\nOutput: 3\nExplanation: Performing the test operations in order starting from device 0:\nAt device 0, batteryPercentages[0] > 0, so there is now 1 tested device, and batteryPercentages becomes [1,0,1,0,2].\nAt device 1, batteryPercentages[1] == 0, so we move to the next device without testing.\nAt device 2, batteryPercentages[2] > 0, so there are now 2 tested devices, and batteryPercentages becomes [1,0,1,0,1].\nAt device 3, batteryPercentages[3] == 0, so we move to the next device without testing.\nAt device 4, batteryPercentages[4] > 0, so there are now 3 tested devices, and batteryPercentages stays the same.\nSo, the answer is 3.\n
\n\n

Example 2:

\n\n
\nInput: batteryPercentages = [0,1,2]\nOutput: 2\nExplanation: Performing the test operations in order starting from device 0:\nAt device 0, batteryPercentages[0] == 0, so we move to the next device without testing.\nAt device 1, batteryPercentages[1] > 0, so there is now 1 tested device, and batteryPercentages becomes [0,1,1].\nAt device 2, batteryPercentages[2] > 0, so there are now 2 tested devices, and batteryPercentages stays the same.\nSo, the answer is 2.\n
\n\n

 

\n

Constraints:

\n\n\n", "translatedTitle": "统计已测试设备", "translatedContent": "

给你一个长度为 n 、下标从 0 开始的整数数组 batteryPercentages ,表示 n 个设备的电池百分比。

\n\n

你的任务是按照顺序测试每个设备 i,执行以下测试操作:

\n\n\n\n

返回一个整数,表示按顺序执行测试操作后 已测试设备 的数量。

\n\n

 

\n\n

示例 1:

\n\n
\n输入:batteryPercentages = [1,1,2,1,3]\n输出:3\n解释:按顺序从设备 0 开始执行测试操作:\n在设备 0 上,batteryPercentages[0] > 0 ,现在有 1 个已测试设备,batteryPercentages 变为 [1,0,1,0,2] 。\n在设备 1 上,batteryPercentages[1] == 0 ,移动到下一个设备而不进行测试。\n在设备 2 上,batteryPercentages[2] > 0 ,现在有 2 个已测试设备,batteryPercentages 变为 [1,0,1,0,1] 。\n在设备 3 上,batteryPercentages[3] == 0 ,移动到下一个设备而不进行测试。\n在设备 4 上,batteryPercentages[4] > 0 ,现在有 3 个已测试设备,batteryPercentages 保持不变。\n因此,答案是 3 。\n
\n\n

示例 2:

\n\n
\n输入:batteryPercentages = [0,1,2]\n输出:2\n解释:按顺序从设备 0 开始执行测试操作:\n在设备 0 上,batteryPercentages[0] == 0 ,移动到下一个设备而不进行测试。\n在设备 1 上,batteryPercentages[1] > 0 ,现在有 1 个已测试设备,batteryPercentages 变为 [0,1,1] 。\n在设备 2 上,batteryPercentages[2] > 0 ,现在有 2 个已测试设备,batteryPercentages 保持不变。\n因此,答案是 2 。\n
\n\n

 

\n\n

提示:

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"cpp", "code": "class Solution {\npublic:\n int countTestedDevices(vector& batteryPercentages) {\n \n }\n};", "__typename": "CodeSnippetNode" }, { "lang": "Java", "langSlug": "java", "code": "class Solution {\n public int countTestedDevices(int[] batteryPercentages) {\n\n }\n}", "__typename": "CodeSnippetNode" }, { "lang": "Python", "langSlug": "python", "code": "class Solution(object):\n def countTestedDevices(self, batteryPercentages):\n \"\"\"\n :type batteryPercentages: List[int]\n :rtype: int\n \"\"\"", "__typename": "CodeSnippetNode" }, { "lang": "Python3", "langSlug": "python3", "code": "class Solution:\n def countTestedDevices(self, batteryPercentages: List[int]) -> int:", "__typename": "CodeSnippetNode" }, { "lang": "C", "langSlug": "c", "code": "int countTestedDevices(int* batteryPercentages, int batteryPercentagesSize) {\n \n}", "__typename": "CodeSnippetNode" }, { "lang": "C#", "langSlug": "csharp", "code": "public class Solution {\n public int CountTestedDevices(int[] batteryPercentages) {\n\n }\n}", "__typename": "CodeSnippetNode" }, { "lang": "JavaScript", "langSlug": "javascript", "code": "/**\n * @param {number[]} batteryPercentages\n * @return {number}\n */\nvar countTestedDevices = function(batteryPercentages) {\n\n};", "__typename": "CodeSnippetNode" }, { "lang": "TypeScript", "langSlug": "typescript", "code": "function countTestedDevices(batteryPercentages: number[]): number {\n \n};", "__typename": "CodeSnippetNode" }, { "lang": "PHP", "langSlug": "php", "code": "class Solution {\n\n /**\n * @param Integer[] $batteryPercentages\n * @return Integer\n */\n function countTestedDevices($batteryPercentages) {\n\n }\n}", "__typename": "CodeSnippetNode" }, { "lang": "Swift", "langSlug": "swift", "code": "class Solution {\n func countTestedDevices(_ batteryPercentages: [Int]) -> Int {\n\n }\n}", "__typename": "CodeSnippetNode" }, { "lang": "Kotlin", "langSlug": "kotlin", "code": "class Solution {\n fun countTestedDevices(batteryPercentages: IntArray): Int {\n\n }\n}", "__typename": "CodeSnippetNode" }, { "lang": "Dart", "langSlug": "dart", "code": "class Solution {\n int countTestedDevices(List batteryPercentages) {\n \n }\n}", "__typename": "CodeSnippetNode" }, { "lang": "Go", "langSlug": "golang", "code": "func countTestedDevices(batteryPercentages []int) int {\n\n}", "__typename": "CodeSnippetNode" }, { "lang": "Ruby", "langSlug": "ruby", "code": "# @param {Integer[]} battery_percentages\n# @return {Integer}\ndef count_tested_devices(battery_percentages)\n\nend", "__typename": "CodeSnippetNode" }, { "lang": "Scala", "langSlug": "scala", "code": "object Solution {\n def countTestedDevices(batteryPercentages: Array[Int]): Int = {\n\n }\n}", "__typename": "CodeSnippetNode" }, { "lang": "Rust", "langSlug": "rust", "code": "impl Solution {\n pub fn count_tested_devices(battery_percentages: Vec) -> i32 {\n\n }\n}", "__typename": "CodeSnippetNode" }, { "lang": "Racket", "langSlug": "racket", "code": "(define/contract (count-tested-devices batteryPercentages)\n (-> (listof exact-integer?) exact-integer?)\n )", "__typename": "CodeSnippetNode" }, { "lang": "Erlang", "langSlug": "erlang", "code": "-spec count_tested_devices(BatteryPercentages :: [integer()]) -> integer().\ncount_tested_devices(BatteryPercentages) ->\n .", "__typename": "CodeSnippetNode" }, { "lang": "Elixir", "langSlug": "elixir", "code": "defmodule Solution do\n @spec count_tested_devices(battery_percentages :: [integer]) :: integer\n def count_tested_devices(battery_percentages) do\n \n end\nend", "__typename": "CodeSnippetNode" } ], "stats": "{\"totalAccepted\": \"5.2K\", \"totalSubmission\": \"6.1K\", \"totalAcceptedRaw\": 5189, \"totalSubmissionRaw\": 6135, \"acRate\": \"84.6%\"}", "hints": [ "One solution is simulating the operations as explained in the problem statement, and it works in O(n2) time.", "While going through the devices, you can maintain the number of previously tested devices, and the current device can be tested 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